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defon
3 years ago
12

How do I simplify and solve for x for 3x-7=2

Mathematics
2 answers:
saul85 [17]3 years ago
8 0
3x-7=2\ \ \ \ \ \ \ \ |add\ 7\\\\3x=2+7\\\\3x=9\ \ \ \ \ \ \ |:3\\\\x=3\\
Norma-Jean [14]3 years ago
8 0
3x-7=2\\
3x=9\\
x=3
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Harlamova29_29 [7]

We compute the productivity percentage change of each category using the formula:

\text{\% Change }=\frac{\text{ Value now - Value last year}}{\text{Value last year}}\cdot100\%.

Productivity percentage change for each category

1) Units produced:

\frac{1,000-1,000}{1,000}\cdot100\%=0\cdot100\%=0\%.

2) Last (hours)

\frac{275-300}{300}\cdot100\%=-\frac{25}{300}\cdot100\%=-8.33\%.

3) Resin (pounded)

\frac{45-50}{50}\cdot100\%=-\frac{5}{50}\cdot100\%=-10\%.

4) Capital invested ($)

\frac{11,000-10,000}{10,000}\cdot100\%=\frac{1,000}{10,000}\cdot100\%=10\%.

5) Energy (BTU)

\frac{2,850-3,000}{3,000}\cdot100\%=\frac{-150}{3,000}\cdot100\%=-5\%.

2) Improvement for labour hours

From the previous computations, we see that the percentage change of the category "Last (hours)" has a negative value of -8.33%, which means that this value decreased by 8.33% with respect to the last year.

Answer

1) Productivity percentage change for each category

0. Units produced: ,0%

,

1. Last (hours): , -8.33%

,

2. Resin (pounded):, -10%

,

3. Capital invested ($): ,10%

,

4. Energy (BTU): ,-5%

2) Improvement for labour hours

The percentage change of the category "Last (hours)" has a negative value of -8.33%, which means that this value decreased by 8.33% with respect to the last year.

4 0
2 years ago
Polygon JKLM is dilated by a scale factor of 2.5 with point C as the center of dilation, resulting in the image J′K′L′M′. If poi
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3 years ago
The Petrol tank of a car was full at the start of a Journey and contained 50 liters. After completing two thirds of the Journey
Naddik [55]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Vertical angle question, should be easy points for you
Luba_88 [7]
ANSWER: A & B

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5 0
3 years ago
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Mark is draining his pool to clean it. At 12:00 P.M., he started to drain the pool. At 4:00 P.M., the pool had 11,600 gallons of
katrin2010 [14]
12:00 P.M. to 7:00 P.M. is a total of 7 hours.
4:00 P.M. to 7:00 P.M. is a total of 3 hours.

This means that from 4:00 p.m to 7:00 P.M. this represents 3/7 of what was lost from 12:00 P.M. to 7:00 P.M.

After knowing this, after doing 11,600 - 6,800 = 4,800
4,800 represents 3/7 of what was lost for 7 hours.
We then divide 4,800 by 3 which gets 1,600.

Because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.  After adding 11,200 to how much water was left at 7:00 P.M. which was 6,800. 11,200 + 6,800 = 18,000

This means that the pool originally had 18,000 gallons in the pool.

You can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.
6 0
3 years ago
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