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3 years ago

How do I simplify and solve for x for 3x-7=2

Mathematics

2 answers:

saul85 [17]3 years ago

8 0

$3x-7=2\ \ \ \ \ \ \ \ |add\ 7\\\\3x=2+7\\\\3x=9\ \ \ \ \ \ \ |:3\\\\x=3\\$

Norma-Jean [14]3 years ago

8 0

$3x-7=2\\
3x=9\\
x=3$

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$\frac{45-50}{50}\cdot100\%=-\frac{5}{50}\cdot100\%=-10\%.$

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5) Energy (BTU)

$\frac{2,850-3,000}{3,000}\cdot100\%=\frac{-150}{3,000}\cdot100\%=-5\%.$

2) Improvement for labour hours

From the previous computations, we see that the percentage change of the category "Last (hours)" has a negative value of -8.33%, which means that this value decreased by 8.33% with respect to the last year.

Answer

1) Productivity percentage change for each category

0. Units produced: ,0%

1. Last (hours): , -8.33%

2. Resin (pounded):, -10%

3. Capital invested ($): ,10%

4. Energy (BTU): ,-5%

2) Improvement for labour hours

The percentage change of the category "Last (hours)" has a negative value of -8.33%, which means that this value decreased by 8.33% with respect to the last year.

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Mark is draining his pool to clean it. At 12:00 P.M., he started to drain the pool. At 4:00 P.M., the pool had 11,600 gallons of

katrin2010 [14]

12:00 P.M. to 7:00 P.M. is a total of 7 hours.
4:00 P.M. to 7:00 P.M. is a total of 3 hours.

This means that from 4:00 p.m to 7:00 P.M. this represents 3/7 of what was lost from 12:00 P.M. to 7:00 P.M.

After knowing this, after doing 11,600 - 6,800 = 4,800
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We then divide 4,800 by 3 which gets 1,600.

Because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200. After adding 11,200 to how much water was left at 7:00 P.M. which was 6,800. 11,200 + 6,800 = 18,000

This means that the pool originally had 18,000 gallons in the pool.

You can also check your work by doing 18,000 - 4(1600), which becomes 1800 - 6400 which gets you 11,600.

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