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Natali [406]
3 years ago
7

You start driving north for 9 miles, turn right, and drive east for another 40 miles. At the end of driving, what is your straig

ht line distance from your starting point?
Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

The straight line distance from the starting point is 41 miles.

<u>Explanation:</u>

Given:

Distance covered towards north, n = 9 miles

Distance covered towards east, e = 40 miles

Distance from the origin to the end, x = ?

If we imagine this, then the route forms a right angle triangle

where,

n is the height

e is the base

x is the hypotenuse

Using pythagoras theorm:

(x)² = (n)² + (e)²

(x)² = (9)² + (40)²

(x)² = 1681

x = 41 miles

Therefore, the straight line distance from the starting point is 41 miles.

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For ABC:

The interior angle of C is 180 - 142 = 38
The three interior angles add up to 180°
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The measure of angle ABC = x - 5 = 54 - 5 = 49

For JKL:
The interior angle of L is 180 - 100 = 80°
The 3 interior angles add up to 180°
(2x + 27) + (2x - 11) + 80 = 180
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Technical improvement of a factory enabled it to produce 165 parts more in February than in January. In the two-month period, th
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Please find the answer to this function! F(2)= 6x^4-10x^3+40x-50
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<u>Answer-</u>

f(2)= 6x^4-10x^3+40x-50=46

<u>Solution-</u>

The given function is,

\Rightarrow f(x)= 6x^4-10x^3+40x-50

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50

\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50

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\Rightarrow f(2)= 96-50

\Rightarrow f(2)= 46

Therefore, f(2) was found to be 46.


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4 years ago
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