The <em>correct answer</em> is:
Place the point of the compass on the vertex of our original angle. Open the compass to a random width and draw an arc through both legs of the angle. Mark the points of intersection with this arc and the sides of the angle.
Explanation:
In order to copy the angle, we need to have some reference for how wide the angle is.
So far all we have is a ray. To get the reference for the width that we need, we will construct an arc in the original angle such that it intersects each side of the angle.
We will then set the compass width to these points of intersection. This will be how we set the width of the new angle.
This is the best I got Require to make 2 equations with the same repeating part and subtract them to eliminate the repeating part.
begin by letting x = 0.5555555................. (1)
To obtain the same repeating part after the decimal point need to multiply by 10
hence 10x = 5.555555........................(2)
It is important to obtain 2 equations in x, where the recurring part after the decimal points are exactly the same.
now subtract (1) from (2) to obtain fraction
(2) - (1) : <span>9x=5⇒x=<span><span>59</span></span></span>
22 kilometers :) hope that helped
Answer:A=8-1/57=455/57=7.98
Step-by-step explanation:
Answer:
<em>Hence the daughter's present age is 15 years</em>
<em>The fathers present age is 35 years</em>
<em></em>
Step-by-step explanation:
Let the present age of daughter be x
Let the present age of father be y
5 years ago;
Daughter's age = x - 5
Fathers age = y - 5
If the present age of father is thrice as old as the age of daughter 5 years ago, then;
y - 5 = 3(x-5)
y - 5 = 3x-15
y = 3x - 10 .... 1
In 5 years time;
Daughters age = x + 5
Fathers age = y + 5
If the age of father will be twice the age of his daughter in 5 years time then;
y+5 = 2(x+5)
y+5 = 2x + 10
y = 2x + 5 .....2
Equate 1 and 2;
3x - 10 = 2x + 5
3x - 2x = 5 + 10
x = 15
Since y = 2x + 5
y = 2(15) + 5
y = 35
<em>Hence the daughter's present age is 15 years</em>
<em>The fathers present age is 35 years</em>
<em></em>
