Answer:
<h3><u>Mean</u></h3>
<u />



<h3><u>Standard Deviation</u></h3>



<h3><u>Summary</u></h3>
Nilo has a mean score of 10 and a standard deviation of 5.23.
Lisa has a mean score of 10 and a standard deviation of 1.83.
The <u>mean</u> scores are the <u>same</u>.
Nilo's standard deviation is higher than Lisa's. Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.
Answer:
false
Step-by-step explanation:
False
5(9)(3.2)
45*3.2=144
Hope this helps :)
Answer:
y+11=-2/3(x-6)
Step-by-step explanation:
To find the parallel line, we would just plug in the numbers in the point-slope form from what we're given. We have y=-2/3x+12 and (6,-11).
Point-slope form:
y-y1=m(x-x1) → y+11=-2/3(x-6)
m represents the slope, which is -2/3 in this situation.
y1 represents the y coordinate, which is -11 in this situation. However, when we plug in negative numbers in a point-slope form, we would do the opposite of the negative number, which is to make it a positive in point-slope form.
x1 represents the x coordinate, which is 6 in this situation.