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Charra [1.4K]
3 years ago
12

Is (2, 2) a solution of y < 4x - 6? Choose 1 answer yes or no

Mathematics
1 answer:
zalisa [80]3 years ago
4 0

No, (2,2) is not solution of y < 4x - 6

Step-by-step explanation:

To solve above linear problem, we use standard method of  Back- Substitution.

First of all, A point (2,2) only becomes solution of equation, if it satisfies equation y < 4x - 6.

Here, the  y < 4x - 6  seems to be like a linear equation.

In this Equation, using  Back- Substitution method,

Point (2,2) : first digit 2 corresponds to x- coordinate and second digit 2 corresponds to y-coordinate.

           y < 4x - 6.....(1)     \\\         x= 2        .....(2)       \\\       y= 2        .....(3)

By putting value of x and y in equation (1),

Equation becomes,

        2 <  4 \times 2  - 6

       2 < 8       -  6

       2 <  2      .... not true mathematically.

Finally, the result came is not true. Therefore, (2,2) is not solution for equation

y < 4x - 6          

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Given a line segment with endpoints A(16, 8) and B(1, 3) what are the coordinates of the
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Answer:

The line segment partitioned two-fifths from A to B is (10,6)

Step-by-step explanation:

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than find the difference between A to B i.e B - A

(1,3)-(16,8) = (-15,-5)

To measure the (2/5) difference we will multiply (-15,-5) with  (2/5) which is equal to (-6,-2)

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2. A statistics student plans to use a TI-84 Plus calculator on her final exam. From past experience, she estimates that there i
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Answer:

  1. P(≥1 working) = 0.9936
  2. She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.

Step-by-step explanation:

1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...

... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936

2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.

If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.

This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.

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