2 years ago

write an equation of the line that passes through the given point is a parallel and B perpendicular to the given line (4,3)

Mathematics

1 answer:

Anni [7]2 years ago

3 0

Answer:

I need more information to solve

Step-by-step explanation:

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Natali5045456 [20]

Answer:

$-x^2+24x-70$

Step-by-step explanation:

$(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5 - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70$

Formula used =

$(a-b)^2 = a^2+ 2ab + b^2$

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2 years ago

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gtnhenbr [62]

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3 years ago

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pickupchik [31]

Answer:

38.68 degrees

Step-by-step explanation:

In this equation you are trying to find the degrees using the hypotenuse and opposite. So you have to use the function sin^-1(5/8). Because when using Sin it is opposote ove hypotenuse.

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3 years ago

write an equation of the line that passes through the given point is a parallel and B perpendicular to the given line (4,3)​

write an equation of the line that passes through the given point is a parallel and B perpendicular to the given line (4,3)