What is the area of the rectangle part of the following composite figure
2 answers:
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The equation of the line is, .
Given that,
The equation of the line is,
And contains the point (-2, -5).
We have to determine,
What is the equation of the line that is perpendicular to the given line?
According to the question,
The equation of the line is,
On comparing with the standard equation of the line y = mx +c.
The slope of the line is 1/3.
When two lines are perpendicular the relation between these slopes is,
And line contains the point (-2, -5).
Then,
Therefore,
The equation of the line that is perpendicular to the given line and contains the point (-2, -5) is,
Hence, The required equation of the line is, .
For more details refer to the link given below.
Answer:
Perimeter
P = P1+P2
P1 = 4a P2=2(a+b)
P1=4*5 P2=2(3+5)
P1=20 P2=2*8
P2=16
P = 20+16
P=36
Area
A=A1+A2
A1= A2=a*b
A1= A2=3*5
A1=25 A2=15
A=25+15
A=40
One way you could solve this is to just multiply the top and bottom out so that you get 9/81, reducing it by 9/9 to get 1/9 or option C.
Another way would be to do
since dividing numbers with exponents would be subtracting the bottom exponent from the top exponent, provided that the base number (in this case 3) is the same for both. For this method, you would get 
, which is equal to 1/9 or .1 repeating, the same answer that you'd get with the first method.
Another way would be to do