The density of ice is approximately 0.92 g/cm3 . If a block of ice has a volume of 2300 cm3, what is its mass?
1 answer:
Answer:
The mass of the ice block is 2116 grams ⇒ a
Step-by-step explanation:
The formula of density is , where m is the mass and V is the volume
To find the mass from this formula multiply both sides by V,
then m = p.V
∵ The density of ice is approximately 0.92 g/cm³
∴ p = 0.92
- That means the mass of 1 cm³ is 0.92 g
∵ The volume of an ice block is 2300 cm³
∴ V = 2300
- Use the formula of the mass
∵ m = p.V
- Substitute the values of p and V in it
∴ m = (0.92)(2300)
∴ m = 2116 grams
The mass of the ice block is 2116 grams
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Answer:
Step-by-step explanation:
Given that the figure is made up of portion of a square and a semicircle, we have;
BC ≅ AB = 6 cm
The area of semicircle BC with radius BC/2 = 3 is 1/2×π×r² = 1/2×π×3² = 4.5·π cm²
Triangle ABC = 1/2 × Area of square from which ABC is cut
The area of triangle ABC = 1/2×Base ×Height = 1/2×AB×BC = 1/2×6×6 = 18 cm²
The area of the figure = The area of semicircle BC + The area of triangle ABC
The area of the figure = 4.5·π cm² + 18 cm² = .