A the bacteria growth increases exponentially
Answer:
1/(m^4*n^2
Step-by-step explanation:
The given expression is
(m^2*n^-3)/(m^6*n^-1)
Tyrone's approach.
Raising the expression to the 3rd power will not help. It will make the expression more complicated.
Alisha's approach.
(m^2*n^-2)/(m^6*n^-1)
= m^(2-6)*n^(-3+1)
= m^-4*n^-2
= 1/(m^4*n^2)
Alisha's approach will simplify the expression to 1/(m^4*n^2
Answer:
I think 4
Step-by-step explanation:
If FG = 2 and EF looks very similar, EG would be 4 and EH=8, 8-4=4
Answer:
About 41.5%
Step-by-step explanation:
<em>Given:</em>
<em>A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape.</em>
<em>To Find:</em>
<em>What is the probability that both grapes are red?</em>
<em>Answer choices:</em>
<em>about 39.7%</em>
<em>about 41.5%</em>
<em>about 42.5%</em>
<em>about 44.5%</em>
<em>Solution:</em>
<em>Since, there are 8 green grapes and 15 red grapes, the total number of grapes is 23 .</em>
<em>As the red grapes are 15..</em>
<em>Thus,</em>
<em>The probability of choosing a red grape the first time is 15/23.</em>
<em>Because out of the total 23 grapes only 15 were red grape.</em>
<em>The probability of choosing the red grape the second time will be 14/22. Because the number of red grapes has already decreased by one and so is the total number of grapes after first choice</em>
<em>Hence, the probability of choosing or eating two red grapes will be :</em>
<em>15/23×14/22</em>
<em>=105/253</em>
<em>=0.415</em>
<em>= 41.5%</em>
<em>Therefore, the probability that both grapes are red is about 41.5%</em>
