Answer:
The probability of the bus getting there BEFORE 8:20 isn't likely
I took an average of all of the numbers and its shows that he bus will be there about 8:20.25
Answer:
The question isn't completely clear, but I believe that the answer would be 7m. That is the correct format.
Answer:
A=B=C... wouldn't both B and C be equal to A? Also I can't see the statements.
Answer:
P(X > 5) = 0.1164 to 4 d.p.
The parameters are defined in the explanation.
Step-by-step explanation:
This is a binomial distribution problem
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of potential hires = 10
x = Number of successes required = number of potential hires that have prior call centre experience = more than half; that is, x > 5
p = probability of success = probability that any potential hire will have experience = (11/30) = 0.367
q = probability of failure = probability that any potential hire will NOT have experience = 1 - p = 1 - 0.367 = 0.633
P(X > 5) = P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10)
Inserting the parameters and computing the probabilities for each of those values of X,
P(X > 5) = 0.11641775484 = 0.1164 to 4 d.p.
Hope this Helps!!!
Answer:
hnnnnnnnnnnnnnnnnnnnnnnnnnn
