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ra1l [238]
2 years ago
12

What is the Range of the function

Mathematics
1 answer:
balu736 [363]2 years ago
8 0

Answer: Pretty sure its <em>A.  </em>

Step-by-step explanation:

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Anne takes out an $8,000 loan to buy a car. She chooses the 8-year loan at 9.8% interest, and will pay $120.55 per month. What i
Rufina [12.5K]
You multiply all of them together and then dived by 100 and that's your answer
5 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
Ok I have math hw , and we are doing solving systems of linear equations by graphing and i can’t find where these two lines inte
likoan [24]

Answer:

Line 1, y=-3, x=-3

Line 2, y=2, x=1 1/3

Step-by-step explanation:

6 0
3 years ago
Which expression models the phrase “Wally mowed two more lawns than he mowed last week”?
VLD [36.1K]
Answer: n+2

Two lawns more than last week so two more than something with n being that something is; n+2
4 0
3 years ago
Read 2 more answers
I am having trouble with this question
Marta_Voda [28]
To find the area of a semicircle you would use the formula A=pie * r ^ 2 If you fill in 40 for r you would get 5026.5482
7 0
2 years ago
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