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polet [3.4K]
3 years ago
6

Which of the sets of ordered pairs represents a function? A= {(1, -2), (3, -5), (5, 2), (7, 5)}

Mathematics
2 answers:
miv72 [106K]3 years ago
8 0
Both a and b are functions.
gavmur [86]3 years ago
4 0
A because none of the x values can be repeated in a function
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The probability a randomly selected household owns corporate stock is 0.54. The probability a randomly selected household has no
34kurt

Answer:

30% probability a randomly selected household has no Internet access given the household owns corporate stock

Step-by-step explanation:

I am going to say that we have two events.

Event A: Owning corporate stock. So P(A) = 0.54.

Event B: Having no internet access. So P(B) = 0.3.

Since they are independent events, we can apply the conditional probability formula, which is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probabilitty of event B happening given that A happened. We want to find this.

P(A \cap B) is the probability of both events happening.

Since they are independent

P(A \cap B) = P(A)P(B) = 0.54*0.3

So

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.54*0.3}{0.54} = 0.3

30% probability a randomly selected household has no Internet access given the household owns corporate stock

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For questions 8 – 10, answer the questions about tangent-tangent angles.
olchik [2.2K]

Answer:

m(arc ZWY) = 305°

Step-by-step explanation:

8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,

Angle formed by two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

                                                   = \frac{1}{2}(220-140)

                                                   = \frac{1}{2}(80)

                                                   = 40°

9). Following the same rule as above,

Angle formed between two tangents = \frac{1}{2}(\text{Difference of intercepted arcs})

125 = \frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]

250 = [m(\text{arc ZWY})-m(\text{arc ZY})]

250 = m(arc ZWY) - 55

m(arc ZWY) = 305°

Therefore, measure of arc ZWY = 305° will be the answer.

10). m(arc BAC) = \frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])

                          = \frac{1}{2}(254-106)

                          = \frac{148}{2}

                          = 74°

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3 years ago
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