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3 years ago

120 sweets are shared out into three piles, in

Mathematics

1 answer:

Alja [10]3 years ago

4 0

Answer:

Step-by-step explanation:

3+4+1=8

120/8=15

3:4:1

45:50:15

50-15=35

please mark as brainliest!!<3

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DaniilM [7]

Approximately there are some of these on the we

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2 years ago

What is -2x – 10 = 4????

Sunny_sXe [5.5K]

Answer:

x = -7

Step-by-step explanation:

-2x - 10 = 4

-2x = 14 | Add 10 to both sides

x = -7 | Divide both sides by -2

4 0

3 years ago

Create an equation with the indicated number of solutions.

GenaCL600 [577]

An equation that doesn't have a solution would have to end up as something impossible when you solve it all out, like
5=3.

When you simplify your equation out, you get

3x-4=3x+?

Subtract 3x from both sides.

-4=?

From this, you can tell that you need to out something in the ? that will make the equation false, or something that doesn't equal -4.

You could put anything in the ? as long as it is not -4.

Hope this helps!

4 0

3 years ago

A bag contain 3 black balls and 2 white balls.

Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

$Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\$

$Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}$

Probability of at least one black( means BB or BW or WB)

$=\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}$

Probability of at most one black ( means WW or WB or BW)

$=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}$

a) Probability both black without replacement

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

b) Probability of one black and one white

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

c) Probability of at least one black ( BB or BW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}$

d) Probability of at most one black ( BW or WW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}$

6 0

3 years ago

A cab soup has a radius of 1.65 inches and a height of 4.4 inches how many cubic inches of soup does the can hold? Use 3.14 to a

yawa3891 [41]

Assuming that the cab soup is a cylinder, the volume = $\pi$ $r^{2}$ h
v= 3.14 * (1.65*1.65) * 4.4
1.65*1.65= 2.7225
2.7225 * 4.4 = 11.979
11.979 * 3.14= 37.61406 etc...
v rounded = 37.6

The cab soup can hold up to 37.6 $in^{3}$ of soup.

6 0

3 years ago