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Diano4ka-milaya [45]
3 years ago
7

2. A businessman starts

Mathematics
2 answers:
Leokris [45]3 years ago
4 0

Answer:

0

Step-by-step explanation:

He loses it all in 2 hours

djyliett [7]3 years ago
4 0

Answer:

-25 million

Step-by-step explanation:

Because after 2 hours you will lose all of your money and continue to go down into the negatives.

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Solve for M <br> 6M=2 <br> Simplify your answer as much as possible. 20 Points
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M= 1/3. Hope this helps :)
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Which answer correctly estimates the product of 20.21 × 999.801? A. about 20,000 B. about 2,000 C. about 200 D. about 20
levacccp [35]

20.21 multiplied by 999.801 is 20,205.97821, so the correct answer would be A. about 20,000

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How do I solve x-y=11 2x+y=19
Margarita [4]
<span>x-y=11 2x+y=19
x=11+y
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Find the geometric means in the following sequence.
soldi70 [24.7K]

Answer:

Last choice. d.

Step-by-step explanation:

We are given the first term and the sixth term.

The first term is a_1=-9.

The sixth them is a_6=a_1r^5=-9216.

Let's solve for the common ratio, r.

-9r^5=-9216

Divide both sides by -9:

r^5=1024

Take the fifth root of both sides:

r=1024^{\frac{1}{5}}

r=4

So the common ratio is 4.

a_1=-9

a_2=-9(4)=-36

a_3=-9(4)^2=-144

a_4=-9(4)^3=-576

a_5=-9(4)^4=-2304

a_6=-9(4)^5=-9216

8 0
3 years ago
Find the area of this regular polygon.<br> Round to the nearest tenth.<br> 8.65 mm<br> [? ]mm2
nadezda [96]

Answer:

Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:

a=√{b²+c²−2bc×cos40°}

a=√{149.645−149.645cos40°}

Area Nonagon = (9/4)a²cos40°

=9/4[149.645−149.645cos40°]cot20°

=336.70125[1−cos(40°)]cot(20°)

Applying an identity for the cos(40°) does not get us very far…

= 336.70125[1−(cos2(20°)−1)]cot(20°)

= 336.70125[2−cos2(20°)]cot(20°)

= 336.70125[2−(1−sin2(20°))]cot(20°)

= 336.70125[1+sin2(20°)]cos(20°)sin(20°)

= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²

3 0
3 years ago
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