Answer:
<em>figure</em><em> </em><em>of</em><em> </em><em>cuboid</em>
<em>volume</em><em> </em><em>of</em><em> </em><em>cuboid</em><em>=</em><em>l×</em><em>b</em><em>×</em><em>h</em>
Step-by-step explanation:
(10×3×4)in cube=120incube
1m=100cm
85 cm
400 mm=40 cm
Add up them up and you get 225 cm in total
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
Answer:
x = y - 2 / 2
Step-by-step explanation:
y = 2x + 2
2x + 2 = y
2x = y - 2
x = y - 2 / 2