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VikaD [51]
2 years ago
9

Which ordered pairs represent points on the graph of f(x)=-3 square root over -x ? Check all that apply. (–2, 2) (–1, –1) (0, 0)

(1, –1) (6, –2) (8, –2)

Mathematics
2 answers:
Goryan [66]2 years ago
5 0

Answer:

C, D, F

C: (0,0)

D: (1,-1)

F: (8,-2)

Komok [63]2 years ago
3 0

Answer:

  (-1, -1), (0, 0)

Step-by-step explanation:

Assuming your function is the negative cube root of negative x, the two points listed above are on the curve. (The negatives cancel, so the function reduces to f(x) = ∛x.)

The various points relative to the curve are shown in the attachment.

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3 0
3 years ago
The number of pages that Zev, Kelly, Marneisha, and Aleisha can read in a day is shown below. Zev read 15% of his 56-page book.
Fantom [35]
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6 0
3 years ago
hakeem's frog made 3 quick jumps. the first was 1m. the second was 85cm and the third was 400mm. what was the total length in cm
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4 0
3 years ago
find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}
inn [45]
Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
And x² - 10x - 11=0

Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2  and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2      and  x" = [10 - √64]/2

x' = (10+12)/2    and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
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you will find that both generates an equlity


6 0
3 years ago
Solve y = x2 + 2 for x.
stiks02 [169]

Answer:

x = y - 2 / 2

Step-by-step explanation:

y = 2x + 2

2x + 2 = y

2x = y - 2

x = y - 2 / 2

6 0
2 years ago
Read 2 more answers
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