Question

Write an equation parallel to the function y=-3x+1 and goes through the point (1, -7)

Answer 1

Answer:

Step-by-step explanation:

The parallel lines must have the same slope.

The slope of the given line is 3.

So the parallel line has slope 3 and passes through (1,1)

The general equation of the line is y = m*X + b where m is the slope and b is the intercept.

Solving for B, the intercept is B = y - m*x.

Because (1,1) is on this line X=1, Y=1, and M=3

Plugging them in and substituting:

 B = 1 - 3*1 = 1 - 3 = -2.

So the y-intercept of the parallel line is -2.

The equation of the parallel line is y = 3x + -2 = 3x - 2

The original line crosses the y-axis at y=3, while the parallel line

cross the y-axis at y=-2, which is 4 squares down on the

graph paper. With the slope of 3, M=3 = 3/1 = rise/run -->  up three and on to the right.

You can now draw the graphs.