The answer I think it would be -6 right?
If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)
equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)
So, option D is correct
Answer:
5
Step-by-step explanation:
-6+2n=3n-(6+5)
-6+2n=3n-11
-6+2n-3n=-11
-6-n=-11
n=-6-(-11)
n=-6+11
n=5
