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schepotkina [342]
3 years ago
13

X2 + bx – 12 where b is some whole number (no

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
4 0
It could be pos or neg 4. I know because b is a sum and ac is the product since 12 is negative, there need to be only one negative, and 6 x 2 is 12, so -6 and 2 or 6 and -2
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Identify which equation represents a line perpendicular to the given equation 2x+5y=25
Sonja [21]

Answer:

y = 5/2x + 5

y = 5/2x - 9.5

Step-by-step explanation:

We need to solve for the y in the expresion of 2x + 5y = 25

2x + 5y = 25\\y = (25 - 2x)/5 \\y = 5 - 2/5x

now we re-arrenge the factors in the form y = ax + b

y = -2/5x + 5

we reverse "a"

y = 5/2 + a

And now, we use a point in the other formula to solve for a:

original line:

y = 5 - 2/5x

X = 0 then Y = 5

now we solve for the general equation of the perpendicular equation:

y - y_1 = m ( x - x_1)

y - 5 = 5/2 (x - 0)\\y = 5/2x + 5

If we use a different point we get a different formula:

original line:

y = 5 - 2/5x

X = 5 then Y = 3

y - 3 = \frac{5}{2}(x - 5)\\y - 3 = \frac{5}{2}x -12.5 \\y = \frac{5}{2}x - 9.5

An Image is attached to represent

5 0
3 years ago
Simplify the expression (4x − 3)(x + 5). 4x2 − 17x + 15 4x2 − 17x − 15 4x2 + 17x + 15 4x2 + 17x − 15
DanielleElmas [232]
There are mnemonic acronyms out there for reminding you how to do this. I think of it simply as using the distributive property.
  (4x-3)(x+5) = 4x(x+5) -3(x+5)
then again
  = (4x² +20x) + (-3x -15)
  = 4x² + (20-3)x -15 . . . . . . . combine like terms
  = 4x² +17x -15
5 0
3 years ago
Read 2 more answers
Circle A has area 500 in2. The diameter of circle B is 3 times the diameter of circle A. Estimate the area of circle B.
miv72 [106K]

Answer:

I think 1500 <3

7 0
3 years ago
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Which transformation of triangle T will produce triangle U?
Bezzdna [24]

Answer:A

Step-by-step explanation:

6 0
3 years ago
Find all solutions of the equation in the interval [0, 2π). cotθ+ √3= 0
Ilia_Sergeevich [38]

Answer:

  {5π/6, 11π/6}

Step-by-step explanation:

Since you have memorized the trig values of common angles, you know tan(π/6) = 1/√3, so cot(π/6) = √3.

The solution to this equation is ...

  cot(θ) = -√3

so θ = -π/6 or, in the domain of interest, 11π/6. There is a corresponding quadrant II angle, 5π/6.

5 0
3 years ago
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