Question

What is the following product? (2 StartRoot 7 EndRoot + 3 StartRoot 6 EndRoot) (5 StartRoot 2 EndRoot + 4 StartRoot 3 EndRoot)

Answer 1

Answer:

  $36\sqrt{2}+30\sqrt{3}+10\sqrt{14}+8\sqrt{21}$

Step-by-step explanation:

Use the distributive property and the rules of roots.

  $(2\sqrt{7}+3\sqrt{6})(5\sqrt{2}+4\sqrt{3}) = 10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=\boxed{36\sqrt{2}+30\sqrt{3}+10\sqrt{14}+8\sqrt{21}}$

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(a√b)(c√d) = (ac)√(bd)

√(a²b) = a√b

Answer 2

Answer:

The answer is D on EDGE 2020