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Travka [436]
3 years ago
10

What is the following product? (2 StartRoot 7 EndRoot + 3 StartRoot 6 EndRoot) (5 StartRoot 2 EndRoot + 4 StartRoot 3 EndRoot)

Mathematics
2 answers:
Alisiya [41]3 years ago
8 0

Answer:

  36\sqrt{2}+30\sqrt{3}+10\sqrt{14}+8\sqrt{21}

Step-by-step explanation:

Use the distributive property and the rules of roots.

  (2\sqrt{7}+3\sqrt{6})(5\sqrt{2}+4\sqrt{3}) = 10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=\boxed{36\sqrt{2}+30\sqrt{3}+10\sqrt{14}+8\sqrt{21}}

__

(a√b)(c√d) = (ac)√(bd)

√(a²b) = a√b

aleksandrvk [35]3 years ago
5 0

Answer:

The answer is D on EDGE 2020

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From the given table, we observe that the negative power of 2 reduces by 1 at each step.

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