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Travka [436]
3 years ago
10

What is the following product? (2 StartRoot 7 EndRoot + 3 StartRoot 6 EndRoot) (5 StartRoot 2 EndRoot + 4 StartRoot 3 EndRoot)

Mathematics
2 answers:
Alisiya [41]3 years ago
8 0

Answer:

  36\sqrt{2}+30\sqrt{3}+10\sqrt{14}+8\sqrt{21}

Step-by-step explanation:

Use the distributive property and the rules of roots.

  (2\sqrt{7}+3\sqrt{6})(5\sqrt{2}+4\sqrt{3}) = 10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=\boxed{36\sqrt{2}+30\sqrt{3}+10\sqrt{14}+8\sqrt{21}}

__

(a√b)(c√d) = (ac)√(bd)

√(a²b) = a√b

aleksandrvk [35]3 years ago
5 0

Answer:

The answer is D on EDGE 2020

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If 20 people are participating in an activity, and 15 people decide not to participate. How would i calculate the percentage of
Marta_Voda [28]

Step-by-step explanation:

Solution,

No. of people who participated= 20

No. of people who didn't participated= 15

Total number of people= 20+15= 35

Now,

Percentage of people who didn't participated

=No. of people who didn't participated/Total number of people×100%

=15/35×100%

=42.86%

Again,

Percentage of people who participated

participated=No. of people who participated/Total number of people×100%

=20/35×100%

=57.14%

4 0
3 years ago
Suppose the sound wave has the form y=7cos(3x-pi/6) for x in the interval [pi/6 , 7pi/18]. Express x as a function of y, and sta
Vesnalui [34]

Answer:

x = ⅓ acos(y/7) + π/18, [-7, 7/2]

Step-by-step explanation:

y = 7 cos(3x − π/6)

Solving for x:

y/7 = cos(3x − π/6)

acos(y/7) = 3x − π/6

acos(y/7) + π/6 = 3x

x = ⅓ acos(y/7) + π/18

The domain of x is the same as the range of y.

When x = π/6:

y = 7 cos(3π/6 − π/6)

y = 7 cos(π/3)

y = 7/2

When x = 7π/18:

y = 7 cos(21π/18 − π/6)

y = 7 cos(π)

y = -7

So the domain of x as a function of y is [-7, 7/2].

5 0
4 years ago
Find the common differece of the sequence: 2,9,16,23
riadik2000 [5.3K]
So if 2 is the first term then if n=1 then n+1=sequence so far but

second term is 9 so if n=2 then the 2nd term=9
you must use trial and error to find
so it is
7n-5 so if n=1 then
7(1)-5=7-5=2

if n=2 then
7(2)-5=14-5=9
sucess

the equation is 7n-5

4 0
3 years ago
Read 2 more answers
Which set of equations would have infinite solutions?
vaieri [72.5K]
The answer is b the two equations are equal to each other
4 0
3 years ago
Read 2 more answers
Rewrite the indicated real nth root(s) of a in radical form
notsponge [240]

Answer:

\sqrt[n]{a}

1. \sqrt[3]{27} = \sqrt[3]{3^3} = 3

2. \sqrt[4]{16} = \sqrt[4]{2^4} = 2

3. \sqrt[6]{64} = \sqrt[6]{2^6} = 2

4. \sqrt[5]{243} = \sqrt[5]{3^5} =3

Hope that helps!

7 0
3 years ago
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