Answer:
-6
Step-by-step explanation:
Answer:
25% off $80.00 is <u><em>$60.00 </em></u>
The difference is $20.00
Step-by-step explanation:
Hope this Helps!!!
So it tells us that g(3) = -5 and g'(x) = x^2 + 7.
So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))
now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16
Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84
So we have our linear approximation for the two.
If you wanted to, you could check your answer by finding g(x). Since you know g'(x), take the antiderivative and we will get
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35
So just to check our linear approximations use that to find g(2.99) and g(3.01)
g(2.99) = -5.1597
g(3.01) = -4.8397
So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer. Not a bad method if you ever need to use it.
Answer: (a) 
(b) 
Step-by-step explanation:
(a) P( Bill hitting the target) = 0.7 P( Bill not hitting the target) = 0.3
P( George hitting the target) = 0.4 P(George not hitting the target) = 0.6
Now the chances that exactly one shot hit the target is = 0.7 x 0.6 + 0.4 x 0.3
= 0.54
Chances that George hit the target is = 0.4 x 0.3 = 0.12
So given that exactly one shot hit the target, probability that it was George's shot = 
= .
(b) The numerator in the second part would be the same as of (a) part which is 0.12.
The change in the denominator will be that now we know that the target is hit so now in denominator we include the chance of both hitting the target at same time that is 0.4 x 0.7 and the rest of the equation is same as above i.e.
Given that the target is hit,probability that George hit it = 
= =
5 - 4 + 7x + 1 = 7x + (5 - 4 + 1) = 7x + 2
NO SOLUTIONS:
<em>5 - 4 + 7x + 1 = 7x + a </em><em>(a - any real number, except 2)</em>
ONE SOLUTION:
<em>5 - 4 + 7x + 1 = bx + c </em><em>(b - any real number, except 7, c - any real number)</em>
INFINITELY MANY SOLUTIONS:
<em>5 - 4 + 7x + 1 = 7x + 2</em>
Examples:
2x + 3 = 2x + 5 <em>subtract 2x from both sides</em>
3 = 5 FALSE <em>(NO SOLUTIONS)</em>
2x + 3 = x - 4 <em>subtract x from both sides</em>
x + 3 = -4 <em>subtract 3 from both sides</em>
x = -7 (<em>ONE SOLUTION)</em>
2x + 3 = 2x + 3 <em>subtract 2x from both sides</em>
3 = 3 TRUE <em>(INFINITELY MANY SOLUTIONS)</em>
