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inysia [295]
3 years ago
14

*PLEASE ANSWER ASAP* What is the total volume of the cube below?

Mathematics
2 answers:
Paladinen [302]3 years ago
7 0

Answer:

V = 125 cu.

Step-by-step explanation:

Since volume = L x W x H -->

Plug the numbers in --> 5 x 5 x 5 (5 cubed) -->

25 x 5 = 125

Thus, the total volume of this cube is 125 cu.

Hope this helps!

Brrunno [24]3 years ago
7 0

Answer:

<h3>The answer is option A</h3>

Step-by-step explanation:

Volume of a cube = l³

where l is the length of one side

From the question

there are 5 squares on each side of the cube

So l = 5 units

Volume of the cube = 5³

We have the final answer as

<h3>Volume = 125 cubic units</h3>

Hope this helps you

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Scott has a rope 8 metres long. He says, “I need 9 pieces each 0.89 metres long.” Will Scott have enough ribbon? Explain your an
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1 year ago
Let set A = {odd numbers between 0 and 100} and set B = {numbers between 50 and 150 that are evenly divisible by 5}. What is A ∩
fgiga [73]
<span>A = {odd numbers between 0 and 100}
</span><span>A = {1, 3, 5, 7,...., 95, 97, 99}

B = </span><span>{numbers between 50 and 150 that are evenly divisible by 5}
B = {50, 55, 60, 65, ..., 140, 145, 150}

The notation </span><span>A ∩ B means the set of items that are in set A and also in set B. In terms of venn diagrams, it's the overlapping region between circle A and circle B

In this case, the following values are found in both set A and set B
{55, 65, 75, 85, 95}

So that's why 
</span>A ∩ B = <span>{55, 65, 75, 85, 95}
which is the final answer
</span>
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3 years ago
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Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

1 > (x - 2)/3

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

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2 years ago
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