How many quarters are in $3.50

Please help find the volume

nlexa [21]

Answer:V=375 cubic inches

Step-by-step explanation:

4 0

3 years ago

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Solve the system of equations by substitution X=-4y X+5y=2

maw [93]

Answer:

use -4y for x in the second equation

-4 y + 5 y = 2

so

y = 2

then x = -4(2) = -8

(-8 , 2)

Step-by-step explanation:

4 0

3 years ago

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A student at a junior high school for a seventh and eighth graders wishes to survey all people in the school to find out which m

hammer [34]

Answer:

cars because people are using it everyday i use one

Step-by-step explanation:

i use one

4 0

3 years ago

Hi need help for this maths question

Sauron [17]

a) If f(y) is a probability density function, then both f(y) ≥ 0 for all y in its support, and the integral of f(y) over its entire support should be 1. eˣ > 0 for all real x, so the first condition is met. We have

$\displaystyle \int_{-\infty}^\infty f(y) \, dy = \frac14 \int_0^\infty e^{-\frac y4} \, dy = -\left(\lim_{y\to\infty}e^{-\frac y4} - e^0\right) = \boxed{1}$

so both conditions are met and f(y) is indeed a PDF.

b) The probability P(Y > 4) is given by the integral,

$\displaystyle \int_{-\infty}^4 f(y) \, dy = \frac14 \int_0^4 e^{-\frac y4} \, dy = -\left(e^{-1} - e^0\right) = \frac{e - 1}{e} \approx \boxed{0.632}$

c) The mean is given by the integral,

$\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \int_0^\infty y e^{-\frac y4} \, dy$

Integrate by parts, with

$u = y \implies du = dy$

$dv = e^{-\frac y4} \, dy \implies v = -4 e^{-\frac y4}$

Then

$\displaystyle \int_{-\infty}^\infty y f(y) \, dy = \frac14 \left(\left(\lim_{y\to\infty}\left(-4y e^{-\frac y4}\right) - \left(-4\cdot0\cdot e^0\right)\right) + 4 \int_0^\infty e^{-\frac y4} \, dy\right)$

$\displaystyle \cdots = \int_0^\infty e^{-\frac y4} \, dy$

$\displaystyle \cdots = -4 \left(\lim_{y\to\infty} e^{-\frac y4} - e^0\right) = \boxed{4}$

8 0

2 years ago

Use the two points whose coordinates are shown to find the point-slope form of the equation of the line that models the percent

Shkiper50 [21]

Because there's no picture provided, I can just give two points in order to formulate the equation using the point-slope formula. The x is in years while the y is in percentage. Suppose point 1 is (2, 35) and point 2 is (7,80).

Point Slope Formula: y - y₁ = [(y₂ - y₁)/(x₂ - x₁)](x - x₁)
Substituting,

y - 35 = [(80 - 35)/(7 - 2)](x - 2)
y - 35 = 9(x - 2)

6 0

3 years ago