Answer:
1/7
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(3-2)/(3-(-4))
m=1/(3+4)
m=1/7
Answer:
16.9
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
The 110 degree angle is oppoiste to the angle across it.
Using PLT-C the other angle on the bottom of it should be 70 degrees.
since the 70 degrees is on a straight angle the angle beside it should 110
14(8)-2 = 110
Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:

We substitute x=161.4 ,
, and
to get:

From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Answer:
g(x) = f(x+1) + 1
Step-by-step explanation:
Since the graph is only moved you don't have to worry about the slope.
To move the graph to the left you add to the x and in this case, it only moved 1 over.
to move the graph up you add to the whole function and in this case, it only moved up 1.