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3 years ago

PLEASE HELP 14 POINTS

Mathematics

1 answer:

adoni [48]3 years ago

6 0

$\frac{27}{30} \times 100\% \\ = 90\%$

Approximately 90 percent voted for her

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Solve 6(2/3x-3)>8. The thing says the question is too short and to add at least 20 more words so ignore this sentence, it's o

xxTIMURxx [149]

Answer:

$6(\frac{2x}{3} -3) > 8\\$

Solve brackets

6(0.66x-3)>8

Multiply 6 with values in the bracket

So, 6x0.66x and 6x-3

4x- 18> 8

Since 4x and 18 are unlike terms, we will take 18 onto the other side, thus:

4x>8+18

4x>26

Now to find the value of x, divide 4 on B.S

x> $\frac{26}{4}$

X> 6.5

OR in 'fraction form'

X> $\frac{13}{2}$

Hope this helps :D

5 0

2 years ago

Read 2 more answers

If f(x) = -x3 + 2x2 - 3, find f(2).

algol [13]

F(x)= -2(3)+2(2)2-3=

-6+8-3

-1

I think I solved this correctly....

5 0

3 years ago

Read 2 more answers

Please help will mark Brainliest!!

seraphim [82]

$~~~~~~x+80^{\circ} = 180^{\circ}\\\\\implies x = 180^{\circ} - 80^{\circ}\\\\\implies x = 100^{\circ}$

3 0

2 years ago

Simplify (3a^2-6a+3)/(a^2-1) if a is not 1

AVprozaik [17]

$\dfrac{3a^2-6a+3}{a^2-1}\\\\=\dfrac{3(a^2 -2a+1)}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)^2}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)}{a+1}\\\\=\dfrac{3a-3}{a+1} ~~~\text{for}~ a\neq 1$

7 0

2 years ago

A square has a diagonal that is 26 feet long. What is the perimeter of this square?

Bond [772]

answer:

52 $\sqrt{2}$

step-by-step explanation:

we can use the 45-45-90 triangle theorem for this: x, x, x $\sqrt{2}$

this is because this is a square

squares have two sides of the same length, and the diagonal is different
the x's stand for the sides, whereas the x $\sqrt{2}$ stands for the diagonal

x $\sqrt{2}$ = 26

x = 13 $\sqrt{2}$

now multiply this by 4 because this is the length of one of the sides of the square. in order to find the perimeter we have to either add this four times or multiply by 4

13 $\sqrt{2}$ X 4 = 52 $\sqrt{2}$

5 0

3 years ago