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3 years ago

Perpendicular Vectors:

1 answer:

3 0

1.
v x w = 8 i - 24 j + 15 k + 10 j - 12 i - 24 k =
= - 4 i - 14 j - 9 k
Answer: D )
2.
v x w = -16 i - 16 j - 18 k + 12 j + 48 i - 8 k =
= 32 i - 4 j - 10 k
Answer: C )
3.
The cross product:
< - 6, 7, 2 > x < 8, 5, -3 > =
= - 21 i + 16 j - 30 k - 18 j - 10 i - 56 k =
= - 31 j - 2 j - 86 k = < - 31, - 2, - 86 >
Vectors are perpendicular if: cos ( u, v ) = 0
< - 6 , 7. 2 > * < -31, - 2, - 86 > = 186 - 14 - 172 = 0
< 8, 5 , - 3 > * < - 31, - 2, - 86 > = -248 - 10 + 258 = 0
Answer: A ) < - 31, - 2 , - 86 >, yes.

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A sequence can be generated by using fn = 2f(n-1)+1, where f1 = 4 and n is a whole number greater than 1. What are the first fou

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Answer:

Step-by-step explanation:

<u>Recursive Sequences</u>

The recursive sequence can be identified because each term is given as a function of one or more of the previous terms. Being n an integer greater than 1, then:

f(n) = 2f(n-1)+1

f(1) = 4

To find the first four terms of the sequence, we set n to the values {2,3,4,5}

For n=2

f(2) = 2f(1)+1

Since f(1)=4:

f(2) = 2*4+1

f(2) = 9

For n=3

f(3) = 2f(2)+1

Since f(2)=9:

f(3) = 2*9+1

f(3) = 19

For n=4

f(4) = 2f(3)+1

Since f(3)=19:

f(4) = 2*19+1

f(4) = 39

For n=5

f(5) = 2f(4)+1

Since f(4)=39:

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3 years ago

The number of players in a tennis tournament is reduced by half (50%) after every round. In round 1 there are 256 player, in rou

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Answer:

$a_{n} = a_{1} (\frac{1}{2} )^{n - 1}$ where $a_{1} = 256$ .

The number of players compete in round 7 will be 4.

Step-by-step explanation:

The number of players in a tennis tournament is reduced by half (50%) after every round. In round 1 there are 256 players, in round 2 there are 128 players, and so on.

So, the number of players is multiplied by $\frac{1}{2}$ gives the number of players in the next round.

Therefore, the explicit function of number of players in nth round is given by

$a_{n} = a_{1} (\frac{1}{2} )^{n - 1}$ where $a_{1} = 256$ .

Therefore, the number of players compete in round 7 will be $a_{7} = 256 \times (\frac{1}{2} )^{(7 - 1)} = 4$ . (Answer)

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3 years ago

13 + k3= 11 Show work pls

zaharov [31]

13+3k=11
-Move constant to the right-hand side and change its sign
3k=11-13

Calculate the difference
3k=-2
Divide both sides by 3
K= -2/3

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Answer:

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Step-by-step explanation:

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