Question..
Combine like terms to create an equivalent expression.
½ −⅙q +⅚q - ⅓
Answer:
½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙
Step-by-step explanation:
Given
½ −⅙q +⅚q - ⅓
Required
Equivalence
½ −⅙q +⅚q - ⅓
We start by collecting like terms.
⅚q - ⅙q + ½ - ⅓
Factorize
(⅚ - ⅙)q + ½ - ⅓
((5 - 1)/6)q + ½ - ⅓
(4/6)q + ½ - ⅓
Reduce 4/6 to lowest term
⅔q + ½ - ⅓
Evaluate fraction
⅔q + (3 - 2)/6
⅔q + ⅙
Hence, ½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙
First one is denominator, then opposite of denominator.. i would wait for someone else to answer. but i’m pretty sure that’s correct. sorry if it is incorrect.. good luck on the rest of your assessment!!
If we let x as the number of years of service in the company and f(x) as the increase in the wage, the step wise function that describes the scenario is
f(x) = { 0.5, x < 3
{ 1.0, 3 ≤ x < 6
{ 1.5, 6 ≤ x < 9
{ 2.0, 9 ≤ x < 12
The point (2, 12) represents the wage increase of x < 12
Answer:
The expression giving her net earnings for a day with more than 8 hours worked is X = 80 + 15H, where H means "extra hours worked".
Step-by-step explanation:
Given that Daisy works at an ice-cream parlor earning $10 per hour for the first 8 hours she works in a day, and 1.5 times her hourly wage for every extra hour she works, in order to know how much can she make in a day working more than 8 hours the following equation has to be made:
X = (8 x 10) + (H x (1.5 x 10))
X = 80 + 15H
Therefore, if Daisy works 13 hours, the equation works as follows:
X = 80 + 15x13
X = 80 + 195
X = 275
