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Lapatulllka [165]
3 years ago
5

Is (0,0) a solution to this system y>=x^2+x-4; y<=x^2+2x+1

Mathematics
2 answers:
Anarel [89]3 years ago
8 0

Answer:

It is a solution

Step-by-step explanation:

Check and see if (0,0) satisfies both inequalities.

The first inequality is:

y \geqslant  {x}^{2} + x - 4

When we put x=0, and y=0, we get:

0\geqslant  {0}^{2} + 0 - 4

\implies0\geqslant- 4

This part is true.

The second inequality is:

y \leqslant  {x}^{2}  + 2 x + 1

We put x=0 and y=0 to get:

0 \leqslant  {0}^{2}  + 2 (0) + 1

0 \leqslant 1

This part is also true.

Since the (0,0) not satisfy both, inequalities, it is a solution.

andrew11 [14]3 years ago
4 0

Answer:

yes it is a solution

Step-by-step explanation:

o>-4

0<1

yes both work out to be equal

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Answer:

x = 2

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Multiply both sides by (x-5) and expand:

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