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timofeeve [1]
3 years ago
8

At the Planetarium, tickets cost $10 for adults and $5.50 for kids under 12. How

Mathematics
1 answer:
Bezzdna [24]3 years ago
5 0

Answer:

I do not understand 1234

Step-by-step explanation:

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A quadrilateral has angles that measure 87°, 69°, and 104°. What is the measure of the fourth angle? A. 50° B. 80° C. 100° D. 12
AveGali [126]
C. 100 because a quadrilateral must add up to 360. :)
4 0
3 years ago
Read 2 more answers
−6x+14<−28 OR 9x+15≤−12
Serhud [2]

Answer:x>7 or x ≤ -3

Solving the 1st inequality

-6x +14 < -28 --------------- (Collect like terms)

-6x < -28 - 14

-6x < - 42 -------------------- (Divide both sides by -6)

Note: If you decide an inequality expression by a negative value, the inequality sign changes)

-6x/-6 > -42/-6

x > 7

Solving the 2nd inequality

9x + 15 ≤ −12 ----------- (Collect like terms)

9x ≤ −12 - 15

9x ≤ −27 ------------------(Divide both sides by 9)

9

9x/9 ≤ −27/9

x ≤ -3

Bring both results together, we get

x>7 or x ≤ -3

The final result is complex (i.e. can't be combined together).

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help with question 15 and 16!!!
kykrilka [37]
15. [4] insufficient information. only given SA
16. There are 3 right triangles, 3 Pythagorean theorem equations 
x²+b²= 16²
12²+a² = x²
a²+4² = b²

combine equations using substitution to get in terms of only x
substitute b² for (a² +x²) in first equation
x²+a²+4²=16²
substitute a² for (x² - 12²)
x²+x²-12²+4² = 16²
solve for x
2x² - 144 + 16 = 256
2x² = 256 + 144 - 16
2x² = 384
x² = 384/2
x² = 192
x = 13.85

rounded to nearest tenth, x = 13.9




6 0
3 years ago
Cual es la derivada de ()=√x sin
fgiga [73]

Answer:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

Step-by-step explanation:

We assume that the function of interest is:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

3 0
3 years ago
Select the correct name for the following line.
melomori [17]

option #1 is the correct answer

7 0
3 years ago
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