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Given:
The vertex of a quadratic function is (4,-7).
To find:
The equation of the quadratic function.
Solution:
The vertex form of a quadratic function is:
...(i)
Where a is a constant and (h,k) is vertex.
The vertex is at point (4,-7).
Putting h=4 and k=-7 in (i), we get


The required equation of the quadratic function is
where, a is a constant.
Putting a=1, we get

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Therefore, the required quadratic function is
.
Answer:
f’(x) = x -2/7
Step-by-step explanation:
Let f(x)= y
Thus;
y = x + 2/7
x = y-2/7
So the inverse f’(x) = x - 2/7
Answer:
x = t(a+p)/4
Step-by-step explanation
Given the expression
a=4x/t - p
We are to make x the subject of the formula
a=4x/t - p
Add p to both sides
a+p = 4x/t - p+p
a+p = 4x/t
Cross multiply
t(a+p) = 4x
Rearrange
4x = t(a+p)
Divide both sides by 4
4x/4 = t(a+p)/4
x = t(a+p)/4
Answer:
{(0,0),(0,1),(1,2),(1,3)}
Step-by-step explanation:
If this was a function it would be (0,0) ,(1,1), (2,2) ,(3,3) and so on