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Arturiano [62]
3 years ago
13

List the elements of the set. HINT [See Example 2.] (Enter your answers as a comma-separated list. Enter your answers from small

est to largest.) A = {n | n is a positive integer and 3 < n < 11}.
Mathematics
1 answer:
kaheart [24]3 years ago
8 0

Answer:

<h3>The elements in the set A is {\{4,5,6,7,8,9,10}\}</h3>

Step-by-step explanation:

Given set A={\{n|n is a positive integer and 3

<h3>To list the elements of the given set :</h3>
  • From the given condition in the set A we have the the number n lies between 3 and 11 excluding 3 and 11
  • Since n lies between the open interval (3,11)
  • Therefore the set A={\{4,5,6,7,8,9,10}\}
  • The above set A is arranged from smallest to largest itself.
<h3>The elements in the set A is {\{4,5,6,7,8,9,10}\}</h3>

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A particle moves along a line with a velocity v(t)=t2−t−6, measured in meters per second. Find the total distance the particle t
ahrayia [7]

Answer:

10.67 m

Step-by-step explanation:

Velocity is given as;

v(t) = t² − t − 6

To get the distance, we will integrate the velocity equation.

x(t) = ∫v(t) = (t³/3) - (t²/2) - 6t

Thus, from t=0 seconds to t=4 seconds., we have;

(t³/3) - (t²/2) - 6t between 0 and 4.

Thus;

Total Distance = [(4³/3) - (4²/2) - 6(4)] - [(0³/3) - (0²/2) - 6(0)]

Total distance = (64/3) - 8 - 24 = -10.67 m

Distance can't be negative and so we take the absolute value which is 10.67 m

7 0
3 years ago
1000000000000 x 21392938402840
aivan3 [116]

Answer:

2.1392938e+25Step-by-step explanation: you just times it so u get this answer

4 0
3 years ago
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I have these factoring questions I need help with.
snow_lady [41]

f(x)=4x^2+4x-3

1. Determine y-intercept.

<em>The y-intercept is (0,-3). Substitute x = 0 in the equation as we get f(x) = -3 as the y-intercept.</em>

2. Determine the zeros.

<em>Factor the polynomials first. </em>(2x-1)(2x+3) <em>This is the factored form. The zeros are the roots of equation. Therefore, the zeros are 1/2 and -3/2</em>

3. Determine the Axis of Symmetry

<em>We can solve this by using the formula of </em>x=-\frac{b}{2a}  <em>However, I'll be solving the Axis of Symmetry with Calculus instead.</em>

<em />f'(x)=2(4x^{2-1})+1(4x^{1-1})-0\\f'(x)=8x+4<em />

<em>Then let f'(x) = 0 to find the Axis of Symmetry.</em>

<em />8x+4=0\\8x=-4\\x=-\frac{4}{8}\\x=-\frac{1}{2}<em />

<em>Therefore, the Axis of Symmetry is -1/2</em>

4. Determine the vertex.

<em>Substitute the value of Axis of Symmetry in f(x).</em>

<em />f(x)=4(-\frac{1}{2})^2+4(-\frac{1}{2})-3\\f(x)=4(\frac{1}{4})-2-3\\f(x)=1-2-3\\f(x)=-4<em />

<em>Therefore the vertex is at (-1/2, -4)</em>

5. Does the vertex representing max-pont or min-point?

<em>The vertex represents the minimum point. The graph is upward, meaning the minimum point is the point that gives the LOWEST Y-VALUE. </em>

7. Graph f(x)

<em>Unfortunately I won't be able to graph. But I can tell you to graph a parabola that has the most curve at the vertex and intercepts y-axis at (0,-3).</em>

<em>--------------------------- </em>End of Part 1 --------------------------------

2. Write the general form of Quadratic Function in standard form.

y=ax^2+bx+c

<em>The graph can be easily determined about the y-intercept and being an upward or downward parabola along with how narrow or wide the parabola is. </em>

<em>For example, c value is the y-intercept as defined. When a > 0, the parabola is upward and when a < 0, the parabola is downward. The more value of | a | is, the more narrow it will be and the less value of | a | it is, the wider it will be.</em>

3. Write in Factored Form

y=(x+a)(x+b)\\y=(x-a)(x-b)\\y=(x+a)(x-b)\\y=(x-a)(x+b)

<em>These are factored forms with different types of operators.</em>

<em>The equation can be easily determined about the roots of equation. For example, if the function is in f(x) = (x+2)(x-1) Then the roots would be x = -2 and 1 as the graph will intercept x-axis at (-2,0) and (1,0)</em>

4. Write in Vertex Form.

y=a(x-h)^2+k

<em>The equation can be easily determined for the vertex, axis of symmetry and the same narrow/wide/upward/downward parabola again.</em>

<em>The vertex is at (h,k) and the axis of symmetry is at x = h.</em>

<em>For example, </em>y=(x-2)^2+3<em />

<em>The vertex would be at (2,3) and the axis of symmetry is x = 2.</em>

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3 years ago
A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to
Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

=2\pi r

=(2\times 3.14 \times 32) ft

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0
4 years ago
How to you graph a linear equation when all they say is y=4 what to do
dybincka [34]
-- Find any point where y=4

-- Find another point where y=4

-- With your ruler, draw a line between the two points.
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The equation for every straight line is [ y = mx+b ].

This is the line where (m = 0) and (b = 4).
3 0
3 years ago
Read 2 more answers
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