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algol [13]
3 years ago
12

What is the first step in the constitution of a line perpendicular to AB and passing through an external point M?

Mathematics
1 answer:
NikAS [45]3 years ago
7 0

take your compass on a point on your line. then draw a circle. take the 2 points in which the circle hit the line and draw 2 circles larger than half the distance between he 2 points. take the point that they intersect and and connect it to the line and you point M and it is purpendicular. does that make sense?

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A. 6(k + s)
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14 yd
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Answer:

The volume is 196 cubic yards

Step-by-step explanation:

Given

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Required

The volume

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What is 36/48 simplifiied?
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36/48 simplified is 3/4

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A die is tossed. find the odds against rolling a number greater than 2.
alex41 [277]
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3 0
4 years ago
HELP PLEASE
nordsb [41]

Answer:

<h3>perpendicular line:    y = -¹/₆ x + 4¹/₃ </h3><h3>  parallel line:              y = 6x - 45 </h3>

Step-by-step explanation:

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇔    m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y = 6x - 7   ⇒   m₁=6

6×m₂ = -1        ⇒    m₂ = -¹/₆

 

The line y=-¹/₆ x+b passes through point (8, 3) so the equation:

3 = -¹/₆ ×8 + b must be true

3 = -⁴/₃ + b

b = 4¹/₃

Therefore equation in  slope-intercept form:

                                                     y = -¹/₆ x + 4¹/₃

y=m₁x+b₁   ║   y=m₂x+b₂   ⇔    m₁ = m₂

{Two lines are parallel if  their slopes are equal}

y = 6x - 7   ⇒   m₁=6   ⇒   m₂=6

The line y=6x+b passes through point (8, 3) so the equation:

3 = 6×8 + b must be true

3 = 48 + b

b = -45

Therefore equation in  slope-intercept form:

                                                     y = 6x - 45

7 0
3 years ago
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