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jasenka [17]
3 years ago
5

Renee used the values in the table to calculate sinple intrest

Mathematics
1 answer:
svetlana [45]3 years ago
6 0

Answer: Please supply an image

Step-by-step explanation:

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Answer:yeah it’s 1#

Step-by-step explanation:

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3 years ago
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What is the solution to the system of equations y= -3x+6 y=9
Alex_Xolod [135]

Answer:

<h2>C. (-1, 9)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}y=-3x+6\\y=9\end{array}\right\ \text{put the value of}\ y\ \text{to the first equation}\\\\9=-3x+6\qquad\text{subtract 6 from both sides}\\3=-3x\qquad\text{divide both sides by (-3)}\\-1=x\to x=-1

4 0
3 years ago
What is the sum of the infinite geometric series? Sigma-Summation Underscript n = 1 Overscript 4 EndScripts (negative 144) (one-
Irina18 [472]

The sum of the infinite geometric series is -288.

<h2>Given that</h2>

A finite geometric series with n = 4, a₁ = -144, and r = ½.

<h3>We have to determine</h3>

What is the sum of the infinite geometric series?

<h3>According to the question</h3>

The sum of the infinite is determined by the following formula;

\rm S\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\

A finite geometric series with n = 4, a₁ = -144, and r = ½.

Substitute all the values in the formula;

\rm S\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\S\infty = \dfrac{-144 (1- \dfrac{1}{2}^4)}{1-\dfrac{1}{2}}\\\\S \infty = \dfrac{-144 \times \dfrac{15}{16}}{\dfrac{1}{2}}\\\\S \infty = -270

Therefore,

The sum of the infinite geometric series is,

\rm S = \dfrac{a_1}{1-r}\\\\S=\dfrac{-144}{1-\dfrac{1}{2}}\\\\S = \dfrac{-144}{0.5}\\\\S = -288

Hence, the sum of the infinite geometric series is -288.

To know more about Geometric Series click the link given below.

brainly.com/question/16037289

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2 years ago
Grade Y. 2 Find the slope from two points ZAC
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.....................
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3 years ago
What algebraic expression must be added to the sum of 3x2 +4x+8 and 2x2−6x+3 to give 9x2−2x−5 as the result?
vesna_86 [32]

Answer:

4x^2-16

Step-by-step explanation:

-This is an addition/subtraction problem.

#We subtract the sum of the first two expression from the third expression:

\#Add \ first \ two\\\\=3x^2 +4x+8 +2x^2-6x+3\\\\=5x^2-2x+11\\\\\# Subtract\ from \ the \ third\\=(9x^2-2x-5)-(5x^2-2x+11)\\\\=9x^2-2x-5-5x^2+2x-11\\\\=4x^2-16

Hence, the expression 4x^2-16 must be added to the first two.

7 0
3 years ago
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