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ra1l [238]
3 years ago
13

The new building is 22.5 inches from the gymnasium in the model. What will be the actual

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

67.5feet

Step-by-step explanation:

Given parameters:

Model distance between building and gymnasium  = 22.5 inches

Scale of model :  1 inch  = 3 feet

Unknown:

Actual ground distance  = ?

To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.

In this problem;

    the scale is given as;

                     1 inch on model  represents 3 feet on ground

Now, to find 22.5 inches, simply cross multiply and solve;

        If   1 inch on model  represents 3 feet on ground

              22.5 inches on a model  will be =  \frac{22. 5 inches x 3 feet }{1 inches}

                                                                   = 67.5feet

Therefore, the actual distance is 67.5feet

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I need help please and thank you
Ira Lisetskai [31]

This is a false statement.

When you are solving using square roots, you need to be aware that answers can be both positive and negative. When we solve this, you see there are two possible answers.

x^2 - 9 = 0

x^2 = 9

x = +/- 3

While 3 is an answer, so is -3. If we square either of those numbers, we get 9, which will satisfy the equation.

5 0
3 years ago
A researcher wishes to estimate the number of households with two cars. How large a sample is needed in order to be 99% confiden
solmaris [256]

Answer:

Sample size n = 1382

so correct option is D) 1382

Step-by-step explanation:

given data

confidence level = 99 %

margin of error = 3%

probability = 25 %

to find out

How large a sample size needed

solution

we know here P = 25 %

so 1 - P = 1 - 0.25

1 - P  = 0.75

and we know E margin of error is 0.03 so value of Z for 99%

α = 1 - 99%   = 1 - 0.99

α  = 0.01

and  \frac{\alpha}{2} = \frac{0.01}{2}

\frac{\alpha}{2}  = 0.005

so Z is here

Z_(\frac{\alpha}{2}) = 2.576

so

sample size will be

Sample size n =  (\frac{(Z_(\frac{\alpha}{2})}{E})^2 * P * (1-P)

put here value

Sample size n = (\frac{2.576}{0.03})^2 * 0.25 * 0.75

Sample size n = 1382

so correct option is D) 1382

3 0
4 years ago
How do I find a common denominator for a complex faction when one denominator is 2m-1 and the other is 2m+5
ratelena [41]
The best option is to multiply them together, there would be no value that is common between the two, (2m - 1)(2m + 5), and leave it in this form.

However, there is a second method.
Notice how between the two sits a difference of 6.
You can manipulate one of the fractions to render the same denominator and work from there.
3 0
3 years ago
What percent of 70 is 28?
Mumz [18]

Answer: 40%

Step-by-step explanation:

This represents this equation:

70*x =28

x=28/70=0,4

Multiply that with 100 to get the percentage.

5 0
3 years ago
Read 2 more answers
Which is the equation of an asymptote of the hyperbola whose equation is
goldfiish [28.3K]

Answer:

C. y = 3x - 5

Step-by-step explanation:

Given the general equation of a hyperbola:

\frac{(x-h)^{2} }{a^{2}}-\frac{(y-k)^{2} }{b^{2}}=1

The equation for the asymptote line is given by:

y=k+\frac{b}{a} (x-h)

In your problem, we have

\frac{(x-2)^{2} }{4}-\frac{(y-1)^{2} }{36}=1

we have:

h=2,

k=1

a²=4 --> a=2,    im just taking the squareroot

b²=36 --> b=6

put it into your equation

y=k+\frac{b}{a} (x-h)

y=1+\frac{6}{2} (x-2)

y = 1 + 3(x-2)

y = 1 + 3x - 6

y = 3x - 5

4 0
3 years ago
Read 2 more answers
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