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ra1l [238]
3 years ago
13

The new building is 22.5 inches from the gymnasium in the model. What will be the actual

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

67.5feet

Step-by-step explanation:

Given parameters:

Model distance between building and gymnasium  = 22.5 inches

Scale of model :  1 inch  = 3 feet

Unknown:

Actual ground distance  = ?

To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.

In this problem;

    the scale is given as;

                     1 inch on model  represents 3 feet on ground

Now, to find 22.5 inches, simply cross multiply and solve;

        If   1 inch on model  represents 3 feet on ground

              22.5 inches on a model  will be =  \frac{22. 5 inches x 3 feet }{1 inches}

                                                                   = 67.5feet

Therefore, the actual distance is 67.5feet

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