Use this system of equations to answer the questions that follow. 4x – 9y = 7 –2x + 3y = 4

Mathematics

2 answers:

Vikki [24]3 years ago

6 0

To eliminate x, u would multiply second equation by 2
to eliminate y, u would multiply second equation by 3

Ierofanga [76]3 years ago

6 0

Answer:

Step-by-step explanation:

The given system of equations is 4x - 9y = 7 and -2x + 3y = 4

In this system of equations in order to eliminate the x- terms we will multiply by a number so that coefficients of x may become same.

Therefore, to eliminate the x - terms we multiply second equation by 2.

Similarly to eliminate the y-terms we will multiply the equation by a number so that coefficient of y in both the equations become same.

Therefore, we will multiply second equation by 3.

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Convert 80 km per hour and 120 km per hour to meters per second

Burka [1]

hi brainly user! ૮₍ ˃ ⤙ ˂ ₎ა

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$\large \bold {ANSWER}$

$\large \boxed { \large \sf \green{ 80 km/h = 22.22 m/s }}$
$\large \boxed { \large \sf \green{ 120 km/h = 33.33 m/s }}$

$\large \bold {SOLUTION}$

The first thing we must do is convert kilometers to meters. We will do this by multiplying by 1,000, since 1 km corresponds to 1,000 meters.

80*1000 = 80,000
120*1000 = 120,000

Now that we've done that, let's divide the values by 3,600, because an hour is 60 minutes, and each minute is 60 seconds, so 60*60 is 3,600.

$\frac{80.0\not0\not0}{3.6\not0\not0}=22.22$

$\frac{120.0\not0\not0}{3.6\not0\not0}=33.33$

Hence, 80 km/h = 22.22 m/s, 120 km/h = 33.33 m/s

8 0

2 years ago

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According to the data, Vannessa mean quiz ...

damaskus [11]

Answer: x = 108

Given the below equation

x + 13 1/2 = 121 1/2

Firstly, we need to convert the mixed fraction into an improper fraction

$\begin{gathered} x\text{ + 13}\frac{1}{2}\text{ = 121 }\frac{1}{2} \\ 13\frac{1}{2}\text{ = }\frac{(2\text{ x 13) + 1}}{2} \\ 13\text{ }\frac{1}{2}\text{ = }\frac{26\text{ + 1}}{2} \\ 13\frac{1}{2}\text{ = }\frac{27}{2} \\ 121\frac{1}{2}\text{ = }\frac{(2\text{ x 121) + 1}}{2} \\ 121\frac{1}{2}\text{ = }\frac{243}{2} \\ \text{Therefore, the new equation becomes} \\ x\text{ + }\frac{27}{2}\text{ = }\frac{243}{2} \\ \text{Isolate x} \\ x\text{ = }\frac{243}{2}\text{ - }\frac{27}{2} \\ \text{Common denominator = 2} \\ x=\text{ }\frac{243\text{ - 27}}{2} \\ x\text{ = }\frac{216}{2} \\ x\text{ = 108} \end{gathered}$

8 0

1 year ago

I'm stuck on graphing this quadratic equation:<br><img src="https://tex.z-dn.net/?f=y%20%5Cleqslant%20%20%7Bx%7D%5E%7B2%7D%20%20

rewona [7]

Your welcome I hope it is right