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viva [34]
3 years ago
9

Solve the system of equations. 2x + 7y = 3 x= -4y

Mathematics
1 answer:
I am Lyosha [343]3 years ago
5 0

Answer:

(12, -3)

Step-by-step explanation:

You can solve it algebraically or graphically. Graphically you find the intersection point. Algebraically with substitution/elimination.

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Can someone please help me with this? I don't really understand it and I would really appreciate if you can show me step by step
7nadin3 [17]

Answer:

225

I used

www.symbolab.com

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3 0
3 years ago
Factiorize; y*2-4,is the question​
Viktor [21]

Answer:

(y - 2)(y + 2)

standard factorization!

tadah

4 0
2 years ago
Choose the most convenient method to graph the line x - y = 5.
givi [52]
The most convenient method I would choose is slope-intercept form, which is y=mx+b. So, make this equation equal in terms of y.

x-y=5
subtract x from both sides
-y = 5 - x
multiply both sides by -1 so y isn't negative
y = 5 + x
5 +x is the same thing as x+5, so
y = x+5

Now, you can easily sub in any number for x and you can easily get y. Here are some points you can plot:

(0, 5), (1, 6), (2, 7), (3, 8) and the list goes on. I hope this helped!
7 0
2 years ago
Read 2 more answers
Pls I’m about to cry...
marissa [1.9K]

FORMULA:

  • Volume of cylinder = πr²h
  • Volume of sphere = 4/3πr³

ANSWER:

Volume of capsule = 4/3πr³ + πr²h

πr²(4/3r + h)

  • 3.14 × 2²(8/3 + 5.6)
  • 3.14 × 4(2.6 + 5.6)
  • 12.56(8.2)
  • 102.99 or 103 rounded.

Now, Density = 0.7mg/mm³

  • 0.7/103
  • 0.00679mg

7 0
2 years ago
Elizabeth attempts a field goal by kicking a football from the ground with an initial vertical
sammy [17]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf h(t)=-16t^2+64t+0\implies h(t)=-16t^2+64t\implies \stackrel{\textit{hits the ground}~\hfill }{0=-16t^2+64t} \\\\\\ 0=-16t(t-4)\implies t= \begin{cases} 0\\ \boxed{4} \end{cases}

Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.

5 0
3 years ago
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