All categories

3 years ago

Solve the system of equations. 2x + 7y = 3 x= -4y

Mathematics

1 answer:

I am Lyosha [343]3 years ago

5 0

Answer:

(12, -3)

Step-by-step explanation:

You can solve it algebraically or graphically. Graphically you find the intersection point. Algebraically with substitution/elimination.

You might be interested in

What is (3.1 times 10 Superscript 5 Baseline) (2.2 times 10 Superscript 7 Baseline) in scientific notation? 5.5 times 10 Supersc

aev [14]

Answer:

(B) 6.82 times 10 Superscript 12

Step-by-step explanation:

I just took the quiz

8 0

3 years ago

Read 2 more answers

If sin θ = 3/5 find the value of 4 tanθ + 3 sinθ – 6 cosθ

zepelin [54]

Step-by-step explanation:

If sine theta is 3/5, taking the sine inverse will give you 36.87°.

4tan theta is 4 × tan36.87 = 3

3sin theta = 3 × sin36.87 = 1.8

6cos theta is 6× cos36.87 = 4.8

Therefore, it becomes 3 + 1.8 - 4.8 = 4.8 - 4.8

The answer is 0

5 0

3 years ago

Read 2 more answers

Antonio measures items in his pocket. He knows there

inna [77]

Answer:

8 centimeters

Step-by-step explanation:

10 millimeters = 1 centimeter

80÷x=y 10=x

80÷10=8 8=y

7 0

4 years ago

Solve 270=3e^2.4K to the nearest hundredth

mojhsa [17]

Given:

The equation is:

$270=3e^{2.4K}$

To find:

The solution for the given equation to the nearest hundredth.

Solution:

We have,

$270=3e^{2.4K}$

Divide both sides by 3.

$\dfrac{270}{3}=e^{2.4K}$

$90=e^{2.4K}$

Taking ln on both sides, we get

$\ln (90)=\ln e^{2.4K}$

$\ln (90)=2.4K$ $[\because \ln e^x=x]$

Divide both sides by 2.4.

$\dfrac{\ln (90)}{2.4}=K$

$\dfrac{4.4998}{2.4}=K$ $[\because \ln (90)\approx 4.4998]$

$1.874916667=K$

Round the value to the nearest hundredth (two decimal place)

$K\approx 1.87$

Therefore, the value of K is 1.87.

8 0

3 years ago

Can you guys help and plz be quick

lianna [129]

Answer:

$\displaystyle Bottom\:Right\:Graph$

Step-by-step explanation:

Use the zero-interval test [test point (0, 0)] to verify them as false or true, and to determine whether we shade the shared opposite portions [a shared portion that does NOT contain the origin] or the shared portions that DO contain the origin:

$\displaystyle 0 ≤ 0 - 2 → 0 ≰ -2$

$\displaystyle 0 < -3[0] - 2 → 0 ≮ -2$

So, this system will be shaded in a shared opposite portion.

*NOTE; Both inequalities have an identical y-intercept of $\displaystyle [0, -2],$ so both inequalities must intersect the y-axis at $\displaystyle [0, -2],$ and since there are already lines labeled as <em>dashed</em><em> </em>and solid, we do not have to worry about it in this case.

** None of the other graphs match this, so the bottom right graph has to be it, considering it cut off.

I am joyous to assist you anytime.

5 0

3 years ago