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3 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Mathematics

1 answer:

lions [1.4K]3 years ago

5 0

<h3>Answer: Choice C</h3>

Here's how the verification would look like

$\frac{\sin^2x+\cos^2x}{\cos x} = \sec x$

$\frac{1}{\cos x} = \sec x$ using the identity here

$\sec x = \sec x$

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Cylinder A has a radius of 10 inches and a height of 5 inches. Cylinder B has a volume of 750π. What is the percentage change in

Firlakuza [10]

Answer:

50% change in volume

Step-by-step explanation:

<h2>This problem bothers on the mensuration of solid shapes.</h2>

In this problem we are to find the volume of the first cylinder and compare with the second cylinder.

Given data

Volume v = ?

Diameter d= ?

Radius r = $10 in$

Height h= $5 in$

we know that the volume of a cylinder is expressed as

$volume = \pi r^{2}h$

Substituting our given data we have

$volume = \pi*10^{2}*5\\ volume= \pi *100*5\\volume= 500\pi in^{3} \\$

The first cylinder as a volume of $500\pi$

The change in volume is $750\pi - 500\pi = 250\pi$

percentage = $\frac{250\pi }{500\pi } *100$

$percentage=$ $0.5*100= 50$ %

6 0

3 years ago

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Point \blue{A}Astart color blue, A, end color blue is at \blue{(-4, 8)}(−4,8)start color blue, left parenthesis, minus, 4, comma

ASHA 777 [7]

Answer:

The coordinates of point B are (6,7).

Step-by-step explanation:

Given points are

Blue = A(-4,8)

Purple = M(1,7.5)

Green = B

It is given that point M is the midpoint of point A and B.

Let coordinates of points are (a,b).

Midpoint of two points is

$Midpoint=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})$

$M=(\dfrac{-4+a}{2},\dfrac{8+b}{2})$

Coordinates of midpoint are (1,7.5).

$(1,7.5)=(\dfrac{-4+a}{2},\dfrac{8+b}{2})$

On comparing both sides we get

$1=\dfrac{-4+a}{2}\Rightarrow 2=-4+a\Rightarrow a=6$

$7.5=\dfrac{8+b}{2}\Rightarrow 15=8+b\Rightarrow b=7$

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3 years ago

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olga nikolaevna [1]

Answer:

what are the options?

Step-by-step explanation:

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3 years ago

The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown.

omeli [17]

Answer:

The area of one trapezoidal face of the figure is 2 square inches

Step-by-step explanation:

<u><em>The complete question is</em></u>

The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. What is the area of one trapezoidal face of the figure?

we know that

The area of a trapezoid is given by the formula

$A=\frac{1}{2}(b_1+b_2)h$

where

b_1 and b-2 are the parallel sides

h is the height of the trapezoid (perpendicular distance between the parallel sides)

we have

$h=1\ in\\b_1=1\ in\\b_2=3\ in$

substitute the given values in the formula

$A=\frac{1}{2}(1+3)(1)$

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4 years ago

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otez555 [7]

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3 years ago

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