2(4 + 2x) ≥ 5x + 5
First, we will need to expand our problem. Expanding is basically removing the parentheses. To do this, we will look at the first part of the problem to begin with. 2(4 + 2x). Since parentheses usually mean multiplication, we can start with 2(4). So, 2 × 4 = 8. We'll do the same thing with 2(2), 2 × 2 = 4.
![8 + 4x \ge 5x + 5](https://tex.z-dn.net/?f=8%20%2B%204x%20%5Cge%205x%20%2B%205)
Second, our next step is to subtract 4 from each side. We are trying to get the variable (x) on one side of the problem by itself.
![8 \ge 5x + 5 - 4](https://tex.z-dn.net/?f=8%20%5Cge%205x%20%2B%205%20-%204%20)
Third, we can now simplify (5x) + 5 - (4). I put parentheses around what we are going to focus on. Subtract 5x - 4 to get 1, which can be put as the variable (x). Now we have, x + 5.
![8 \ge x + 5](https://tex.z-dn.net/?f=8%20%5Cge%20x%20%2B%205)
Fourth, let's subtract 5 from each side now. This will set up 8 - 5 which equals 3.
![3 \ge x](https://tex.z-dn.net/?f=3%20%5Cge%20x)
Fifth, we can switch sides now to get the result of this problem.
![x \le 3](https://tex.z-dn.net/?f=x%20%5Cle%203)
Answer:
![7002 \div 52 \\ \\ 134 \ R34 \\ \\ Answer: \fbox {134.6538} \ or \ \fbox {134 R34}](https://tex.z-dn.net/?f=7002%20%5Cdiv%2052%20%5C%5C%20%5C%5C%20134%20%5C%20R34%20%5C%5C%20%5C%5C%20Answer%3A%20%5Cfbox%20%7B134.6538%7D%20%5C%20or%20%5C%20%5Cfbox%20%7B134%20R34%7D)
This problem can be done by using long division. Using long division via online is quite hard.
Answer:
i don't really understand the question?
Step-by-step explanation:
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