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finlep [7]
3 years ago
14

How can the Associative Property be used to mentally find 48 +82? i know the answer is 130. don’t answer the expression plz.❗️❗️

❗️
Mathematics
1 answer:
77julia77 [94]3 years ago
3 0
You can look for friendly numbers such as
48 and 2, split 82 in 80 and 2 and then associate the numbers conveniently

48+ (2+80)=
(48+2)+80=
50+80 which you can do it and is 130 or

50+80=
50+50+30=
100+30 which is 130

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If 3 students make up 10% of the class, how many students are there total in the class?
stealth61 [152]

Answer:

30 students

Step-by-step explanation:

3 students = 10% of the class.

x students = 90% of the class.

(If more, less divides. Let x be the subject. Since we know 10% of the class already, we have to find the remaining 90% that is 100% - 10% = 90%.)

x = 90%/ 10% × 3 students. ( the percentage signs cancel out and so do the zero's.)

x= 9/1 × 3 students ( 9/1 is the same as 9)

x= 27 students

(To find the total, you must add the 10% of the students to the remaining 90% of the students in the class.)

Total number of students in the class = 27 students + 3 students

= 30 students

7 0
2 years ago
The doctor's office where you work needs to store eight filing cabinets with patient information in one of three secure storage
ikadub [295]

Answer:

9 x 7.5

Step-by-step explanation:

Just 9 x 7 = 63 > 55

8 x 5 = 40 < 55

5 x 10 = 50 < 55

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8 0
4 years ago
All movies in a store are being discounted 30%. Let x represent the regular price of a
bagirrra123 [75]
D bc the price is 30 %
4 0
3 years ago
Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits
scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

x^{2} + 3x - 8^{- 14} = 0

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

The above solution is for the quadratic equation of the form:

ax^{2} + bx + c = 0  

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

From the given eqn

a = 1

b = 3

c = - 8^{- 14}

Now, using the above values in the formula mentioned above:

x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)

Now, Rationalizing the above eqn:

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}

x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}

Solving the above eqn:

x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}

Solving with the help of caculator:

x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}

The precise value upto three decimal places comes out to be:

x_{1, 1'} = 0.758\times 10^{- 14}

5 0
3 years ago
Is this function linear or nonlinear?​
Ivahew [28]
Nonlinear. hope this helps :D
4 0
3 years ago
Read 2 more answers
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