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Anvisha [2.4K]
3 years ago
8

Help help help help help help help

Mathematics
2 answers:
Alika [10]3 years ago
4 0

Answer:

105.3

Step-by-step explanation:

Ymorist [56]3 years ago
3 0
The answer is 105.3 I think
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0= -115<br> sin=<br> cos =<br> tan
Alina [70]

Answer:

Step-by-step explanation:

Tito wants to buy some peanut butter to donate as much as possible.

There some brands are given with their price.

we will calculate the price of per ounce peanut butter of each brand.

A. Nutty : 12 ounces for $2.19

cost per ounce =

                        = $0.1825 ≈ $0.18 per ounce

B. Grandma's : 18 ounces for $2.79

cost per ounce =

                        = $0.155 ≈ $0.16 per ounce

C. Bee's : 0.28 ounces for $4.69

cost per ounce =

                        = $16.75 per ounce

D. Save-A-Lot : 40 ounces for $6.60

cost per ounce =

                        = $0.165 ≈ $0.17 per ounce

The lowest price is $0.16 per ounce. So he should buy Grandma's peanut butter.

8 0
3 years ago
A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0
3 years ago
Solve for j. -1j+1&gt;2<br> Please help.
prohojiy [21]
You can use photomath for this
6 0
3 years ago
Hello pls help me answer this correctly!!
anygoal [31]

Answer:

A - 23

B - Finn and 16

Step-by-step explanation:

Counting each box until you get to C gives you 23 and 16 from points A and B

3 0
2 years ago
Which linear inequality is represented by the graph
levacccp [35]

Answer:

The correct awnser is A : )

Step-by-step explanation:

8 0
2 years ago
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