All categories

3 years ago

Write two different expressions that are equal to 12-16x use factoring if possible

Mathematics

2 answers:

guajiro [1.7K]3 years ago

7 0

1) 2(6-8x)

2) 4(3-4x)

That seems about right.

maw [93]3 years ago

7 0

Answer:

$12-16x=4(3-4x)$

$12-16x=2(6-8x)$

Step-by-step explanation:

The expression is $12-16x$ .

One equivalent expression would be if we extract a common factor:

$12-16x=4(3-4x)$

Another equivalent expression would be is we extract a minor common factor:

$12-16x=2(6-8x)$

Therefore, the two expressions are:

$12-16x=4(3-4x)$

$12-16x=2(6-8x)$

You might be interested in

I need help attachment below will give brainliest

Veronika [31]

Answer:

see explanation

Step-by-step explanation:

(1)

Calculate the circumference (C) of the wheel

C = πd (d is the diameter )

= 3.14 × 8 = 25.12 cm

Now divide the distance travelled by the circumference.

times rotated = 12560 ÷ 25.12 ≈ 500

----------------------------------------------------------------

(2)

The area (A) of a circle is calculated as

A = πr² ( r is the radius )

Find r by using the circumference (C)

2πr = 50.24 ( divide both sides by 2π )

r = 50.24 ÷ 6.28 = 8 , then

A = 3.14 × 8² = 3.14 × 64 ≈ 200.96 ft² ( student 3 )

-----------------------------------------------------------------

(3)

C = πd = 3.14 × 30 = 94.2 ≈ 94 m

7 0

2 years ago

Rollie was succesful in losing weight he had a goal weight in mind he went on a diet for three months each month he would lose o

Llana [10]

Let's say that in the beginning he weighted x and at the end he weighted x-y, y being the number of kg he wanted to loose.

first month he lost
y/3

then he lost:
(y-y/3)/3
this is
(2/3y)/3=2/9y
explanation: ((y-y/3) is what he still needed to loose: y minus what he lost already

and then he lost
(y-2/9y-1/3y)/3+3 (the +3 is his additional 3 pounts)
(y-2/9y-1/3y)/3-3=(7/9y-3/9y)/3+3=4/27y+3

it's not just y/3 because each month he lost one third of what the needed to loose at the current time, not in totatl

and the weight at the end of the 3 months was still x-y+3, 3 pounds over his goal weight!

so: x -y/3-2/9y-4/27y-3=x-y+3

we can subtract x from both sides:
-y/3-2/9y-4/27y-3=-y+3
add everything up:

-19/27y=-y+6

which means
-19/27y=-y+6

y-6=19/27y

8/27y=6
4/27y=3
y=20.25

so... that's how much he wanted to loose, but he lost 3 less than that, so 23.25

ps. i hope I didn't make a mistake in counting, let me know if i did. In any case you know HOW to solve it now, try to do the calculations yourself to see if they're correct!

5 0

3 years ago

PLSS HELP ME!! I need to find the value of x

-BARSIC- [3]

Answer:

D. 12°

Step-by-step explanation:

80° + 5x = 140°

or, 5x = 140° - 80°

or, x = 60°/5

:. = 12° Ans

5 0