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Rasek [7]
3 years ago
5

Which of the following is the equation of a circle with center (5, -2) and a radius of 3?

Mathematics
1 answer:
ryzh [129]3 years ago
8 0
EQUATION OF A CIRCLE = (x-h)² + (y-k)² =r²

Since the center of the cercle is in O, then h=5 & k=-2

(x-5)² + (y+2² =9
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The king who retains power by tradition of allegiance ensures that a religious doctrine is enforced as government policy. Which
vaieri [72.5K]

Answer:

The answer is C.This country has both a democracy and a theocracy

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3 years ago
The points A-1,-9) and K(5,1) are endpoints of a diameter of circle 5. Which equation represents circle S?
Lilit [14]

Answer:

A

Step-by-step explanation:

if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is

(x-x1)(x-x2)+(y-y1)(y-y2)=0

reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0

x^{2} +x-5x-5+y^2+9y-y-9=0\\x^{2} -4x+y^2+8y-14=0\\compare with x^2+y^2+2gx+2fy+c=0\\center (-g,-f) \\radius r=\sqrt{g^2+f^2-c}

center is (2,-4)

r=√(2²+(-4)²-(-14))

=√(4+16+14)

=√(34)

eq. of circle is (x-2)²+(y+4)²=34

or

(x²-4x)+(y²+8y)=14

(x²-4x+4)+(y²+8y+16)=14+4+16

(x-2)²+(y+4)²=34

4 0
3 years ago
Solve each pair of simultaneous equations by substitution method
WARRIOR [948]

Answer:

x = 1       y = -4

Step-by-step explanation:

- Plug the value of y into the other equation.

x + 3y = -11

x + 3(-4x) = -11

x - 12x = -11

-11x = -11

x = 1

- Now substitute the value of x into any equation.

y = -4x

y = -4(1)

y = -4

3 0
3 years ago
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loris [4]

<u><em>Answer:</em></u>

108 square units

<h3><u><em>Step-by-step explanation:</em></u></h3>

3 x 4 = 12

3 x 4 = 12

6 x 3 = 18

6 x 3 = 18

6 x 4 = 24

6 x 4 = 24

24(2) + 18(2) + 12(2) = 108 square units

Therefore, the surface area of the rectangular solid below using its net is <u>108 square units</u>

4 0
2 years ago
My snack time calls for 1/2 cup raisins,2/3 cup of nuts and 1/4 cup of chocolate chips what is the combined total
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Answer:1.41666666667 or to simplify, 1.416 but the 6 is repeating so draw a bar over the 6.

Step-by-step explanation:

<h3>  </h3>
6 0
3 years ago
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