Is the following relation a function? (
2 answers:
Answer:
No
Step-by-step explanation:
To check the given graph of a relation is function or not.
Using graph check for function by vertical line test.
Draw numbers of vertical line. If any of one vertical line intersect the graph at two different points then graph is not a function.
Now check the graph using vertical line.
Draw 3 vertical line. All three vertical line intersect graph at two points.
Please have a look in attachment.
So, The graph of relation is not a function because vertical line test not pass.
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Answer: " -2y³ + 3y²<span> + 27y " .
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Refer to the completed chart below (image attached).</span>
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Using the completed chart below (image attached), we can write out the terms:
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y³ − 3y³ + 9y² + 3y² − 9y² + 27y ;
Then, we can combine the "like terms" ;
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y³ − 3y³ = -2y³ ;
+9y² + 3y² − 9y² = + 3y² ;
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to get: -2y³ + 3y² ; and bring down the "+27y" ;
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Answer: " -2y³ + 3y²<span> + 27y " . </span>Refer to chart below (image attached).
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_______________________________________________________
Refer to the completed chart below (image attached).</span>
_______________________________________________________
Using the completed chart below (image attached), we can write out the terms:
__________________________________________________
y³ − 3y³ + 9y² + 3y² − 9y² + 27y ;
Then, we can combine the "like terms" ;
__________________________________________
y³ − 3y³ = -2y³ ;
+9y² + 3y² − 9y² = + 3y² ;
___________________________________________________________
to get: -2y³ + 3y² ; and bring down the "+27y" ;
___________________________________________________________
Answer: " -2y³ + 3y²<span> + 27y " . </span>Refer to chart below (image attached).
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