1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anestetic [448]
3 years ago
11

What is 18 divided by 14?

Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0

if you typed in 8 divided by 14, you'd get 0.5714. You could also express 8/14 as a mixed fraction: 0 8/14.

e-lub [12.9K]3 years ago
4 0

Answer:

1.28571

Step-by-step explanation:

is the answer

You might be interested in
What is 5 less than 15 as an expression
Aleonysh [2.5K]
The phrase "5 less than" means we are subtracting 5 from some amount. And that amount is 15

So, 15 - 5 is the answer.
4 0
4 years ago
Mark is a coin collector. At the first store he went to, he bought 3 sets of 4 coins. At the second store, he bought 5 sets of 3
kramer
Answer: 2 coins

3 • 4 + 5 • 3 - 5 - 8
6 0
4 years ago
What is the domain of the function Y=
Simora [160]

Answer:

x≥-6

Step-by-step explanation:

the set of all numbers for which a function is defined is called domain

for x≥-6 , this function is defined

6 0
3 years ago
A carpet manufacturer is inspecting for flaws in the finished product. If there are too many blemishes, the carpet will have to
OleMash [197]

Answer:

10 square meters will have a standard deviation of 1.897.

Step-by-step explanation:

Standard deviation for n instances of a variable:

If the standard deviation for one instance of a variable is \sigma, for n instances of the variable, the standard deviation will be of s = \sigma\sqrt{n}

The standard deviation of the number of flaws per square yard is 0.6

This means that \sigma = 0.6

For the 10 square yards will a standard deviation of

n = 10, so:

s = \sigma\sqrt{n} = 0.6\sqrt{10} = 1.897

10 square meters will have a standard deviation of 1.897.

5 0
3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
pashok25 [27]

Answer with Step-by-step explanation:

We are given that

f(x,y,z)=10x+10y+3z

g(x,y,z)=5x^2+5y^2+3z^2=43

We have to find the extreme values of the function.

f_x(x,y,z)=10,f_y(x,y,z)=10,f_z(x,y,z)=3

g_x(x,y,z)=10x,g_y(x,y,z)=10y,g_z(x,y,z)=6z

\Delta f(x,y,z)=\lambda \Delta g(x,y,z)

Therefore,

10=\lambda 10x\implies x=\frac{1}{\lambda}

10=10y\lambda\implies y=\frac{1}{\lambda}

3=6z\lambda

z=\frac{1}{2\lambda}

Substitute the values in g(x)

Then, we get

\frac{5}{\lambda^2}+\frac{5}{\lambda^2}+\frac{3}{4\lambda^2}=43

\frac{20+20+3}{4\lambda^2}=43

\frac{43}{4\lambda^2}=43

\lambda^2=\frac{43}{4\times 43}

\lambda=\pm\frac{1}{2}

When \lambda=\frac{1}{2} then,

x=2,y=2,z=1

When \lambda=-\frac{1}{2}

Then, x=-2,y=-2,z=-1

f(2,2,1)=10+10+3=23

f(-2,-2,-1)=-10-10-3=-23

Hence, maximum value of f(x,y,z) is 23 at (2,2,1) and minimum value of f(x,y,z) is -23 at (-2,-2 ,-1).

8 0
4 years ago
Other questions:
  • Mega Fitness charges $22 per month and a $40 sign up fee. If Kenneth has spent a total $370 so far, How many months has he been
    14·1 answer
  • 8/20 greater than or less than 2/10
    6·2 answers
  • Will Joey break his record if he eats 6 hot dogs per
    14·2 answers
  • Which is the first step in simplifying the expression 2(x + 3) + 5?
    11·1 answer
  • Select the two values of x that are roots of this equation.<br> 2x - 3 = -5x2
    5·2 answers
  • 22-28/(14-7)x5+9<br> PEMDAS
    15·1 answer
  • PLEASE HELP ME!! THIS IS 7TH GRADE MATH SO IT SHOULDN’T BE TOO HARD AHHAHA:)
    9·1 answer
  • A school is arranging a field trip to the zoo. The school spends 897.46 dollars on passes for 44 students and 2 teachers. The sc
    13·1 answer
  • Q6. Yesterday Aaron ran 5 km. This morning Aaron ran 4 km. How far did Aaron run altogether?
    9·1 answer
  • Quentin works as a used car salesman, where he earns $8 per hour and an average commission
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!