All categories

2 years ago

(1/12)^-2b•12^-2b+2=12?

Mathematics

1 answer:

Anvisha [2.4K]2 years ago

4 0

Step-by-step explanation:

(1/12)^-2b x 12^-2b+2=12

12^-(-2b) x 12^-2b+2=12

12^2b+(-2b+12)=12

2b-2b+12=12

You might be interested in

Fourth and fifth graders planted trees alongside the road. The distance between two trees is 5 meters how many trees did they pl

Anastaziya [24]

$\mathcal{PROCESS:}$

$\mathbb {DATA \ \ TO\ \ TAKE \ \ INTO \ \ ACCOUNT$

<em>The distance between two trees is 5 meters.</em>
<em>the distance between the first and last trees is 200 meters</em>

<em />

<em>To know the result of trees we will do the following steps...</em>

<em>We will </em><em>divide the distance from the first to the last tree by 5</em><em>, and with this we would have the result:</em>

$200/5=?$

<h3>Result:</h3>

40 trees were planted

<h2><u><em>ATT- Brook2007s</em></u></h2>

6 0

3 years ago

Read 2 more answers

In 44

Andreyy89

Thank you for posting your question here at brainly. The answer to the question "In 44b.c julius caesar was assassinated. rome was founded 691 years earlier in what year was rome founded is <span>735 B.C. I hope the answer will help. </span>

4 0

3 years ago

Given: KLMN is a trapezoid, m∠N= m∠KML, FD=8, LM KN = 3/5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3 root5 Find: KM

Alla [95]

Answer:

The length of KM is $\sqrt{109}$ units.

Step-by-step explanation:

Given information: KLMN is a trapezoid, ∠N= ∠KML, FD=8, $\frac{LM}{KN}=\frac{3}{5}$ , F∈ KL, D∈ MN , ME ⊥ KN KF=FL, MD=DN, $ME=3\sqrt{5}$ .

From the given information it is noticed that the point F and D are midpoints of KL and MN respectively. The height of the trapezoid is $3\sqrt{5}$ .

Midsegment is a line segment which connects the midpoints of not parallel sides. The length of midsegment of average of parallel lines.

Since $\frac{LM}{KN}=\frac{3}{5}$ , therefore LM is 3x and KN is 5x.

$\frac{3x+5x}{2}=8$

$\frac{8x}{2}=8$

$x=2$

Therefore the length of LM is 6 and length of KN is 10.

Draw perpendicular on KN form L and M.

$KN=KA+AE+EN$

$10=6+2(EN)$ (KA=EN, isosceles trapezoid)

$EN=2$

$KE=KN-EN=10-2=8$

Therefore the length of KE is 8.

Use pythagoras theorem is triangle EKM.

$Hypotenuse^2=base^2+perpendicular^2$

$(KM)^2=(KE)^2+(ME)^2$

$(KM)^2=(8)^2+(3\sqrt{5})^2$

$KM^2=64+9(5)$

$KM=\sqrt{109}$

Therefore the length of KM is $\sqrt{109}$ units.

5 0

3 years ago

Write $2.161616 as a fraction and mixed number

Alona [7]

Fraction is 2.161616/1000000
mixed number is 2 161616/1000000

4 0

3 years ago

Please help anyone

Iteru [2.4K]

Answer:

p = 30

Step-by-step explanation:

EFGH is a cyclic quadrilateral ( all vertices lie on a circle )

The opposite angles of a cyclic quadrilateral are supplementary, thus

p + 5p = 180

6p = 180 ( divide both sides by 6 )

p = 30

4 0

3 years ago