Answer:
The margin of error for the survey is 0.016
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 1024
Sample proportion:

We have to find the margin of error associated with a 90% Confidence interval.
Formula for margin of error:


Putting the values, we get:

Thus, the margin of error for the survey is 0.016
Answer:
20 comic books
Step-by-step explanation:
Let us first <u>set up a variable</u>, x, for the number of books that Zoe has. If Jared has 12 more comics than Zoe, he would have x+12 books.
Given that Zoe and Jared have a total of 28 comic books, let us write an <u>equation</u> and solve for x:

Now that we have a <u>simplified</u> version of the equation, let us solve for x by <u>isolating the variable</u> on the left side:

We now know that x=8, and also that Jared has x+12 books. To find the number of comic books Jared has, let us <u>add</u> 12 to x:

Therefore, Jared has 20 comic books.
<em>I hope this helps! Please let me know if you have any further questions :)</em>
Answer:
The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
Answer:
50.4
Step-by-step explanation:
you need to do 15.30 plus 10 which is 15.40 than take that add 25.00 to it and you get 40.4 that 5 plus 5 whixh is 10 ans you get
Bust out a calculator my dear mammal!
600 +
060 +
006 =
666
;)
Have a good one!
Benni OUT!