When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)
Thus there are 11 total possible outcomes.
Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)
This means there are 7 outcomes with sum greater than or equal to 9.
Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11
So, option A gives the correct answer
Answer:
sec or 1/cos
Step-by-step explanation:
1/sin * sin/cos
sin cancels out
1/cos = sec
Slope intercept form: y = mx+ b
m = slope
b = y-intercept
Since we don't have "b", thats what we need to solve for.
-4 = -3/4(8) + b
-4 = 6 + b
-10 = b
Put everything we know back into the original form.
y = -3/4x - 10
Best of Luck!
Answer:
2+2 is 4
Step-by-step explanation:
You can imagine 2 cookies and then you get 2 more which is 4.