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neonofarm [45]
3 years ago
7

Can someone please help with question. I'll give brainliest answer if you help me.

Mathematics
1 answer:
Nikitich [7]3 years ago
6 0

Step-by-step explanation:

Step 1:

(3x + 12y) + (10x - 5y)


<em>{Distributive property A(B+C)=AB+AC}</em>


-------------------

Step 2:

(3x + 12y) + (-5y + 10x)


<em>{Commutative property A+B = B+A}</em>


-------------------

Step 3:

3x + (12y - 5y) + 10x


<em>{Associative property A+(B+C)=(A+B)+C}</em>


-------------------

Step 4:

3x + 10x + (12y - 5y)


<em>{Commutative property A+B = B+A}</em>


-------------------

Step 5:

13x + 7y


<em>{Simplification}</em>


-------------------


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Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

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d) Upper bound = 0.1644

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This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

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H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0

The significance level is 0.05.

The sample 1, of size n1=500 has a proportion of p1=0.36.

p_1=X_1/n_1=180/500=0.36

The sample 2, of size n2=600 has a proportion of p2=0.25.

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The difference between proportions is (p1-p2)=0.11.

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The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277

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z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.11-0}{0.0277}=\dfrac{0.11}{0.0277}=3.964

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P-value=2\cdot P(t>3.964)=0.000078

As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that the accident proportions differ between the two age groups.

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For a 95% CI, the critical value for z is z=1.96.

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The  95% confidence interval for the population mean is (0.0556, 0.1644).

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