(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
52 and 65 those are the ages of principles between 50%
y=5, x=7 because if 3x5=15 then 15-7=8 dont report me if i do get this wrong
Answer:
There is 18% left of the pie.
Step-by-step explanation:
There is only 100% of a pie. If she at 82% then there is 18% left. 100-82=18
First you take 15/10 and see that you can take 5 out of the top and bottom, so it would become 3/2. Now you have 2 3/2. 2 goes into 3 once with 1 remainder so 3/2= 1 1/2
So then you take the original 2 and add it to 1 1/2. The answer is now 3 1/2
