Let's solve your equation step-by-step.<span><span><span>6x</span>−<span>2<span>x4</span></span></span>=<span>12x</span></span><span><span><span>−<span>2<span>x4</span></span></span>+<span>6x</span></span>=<span>12x</span></span>
Step 1: Subtract 12x from both sides.<span><span><span><span>−<span>2<span>x4</span></span></span>+<span>6x</span></span>−<span>12x</span></span>=<span><span>12x</span>−<span>12x</span></span></span><span><span><span>−<span>2<span>x4</span></span></span>−<span>6x</span></span>=0</span>
Step 2: Factor left side of equation.<span><span><span>2x</span><span>(<span><span>−<span>x3</span></span>−3</span>)</span></span>=0</span>
Step 3: Set factors equal to 0.<span><span><span>2x</span>=<span><span><span>0<span> or </span></span>−<span>x3</span></span>−3</span></span>=0</span><span><span>x=<span><span>0<span> or </span></span>x</span></span>=<span>−1.44225</span></span>
Answer:<span><span>x=<span><span>0<span> or </span></span>x</span></span>=<span>−1.44225 This is the answer if its exponent. The other might be:</span></span>
Step 1: Simplify both sides of the equation.<span><span><span>6x</span>−<span>2<span>(<span>4x</span>)</span></span></span>=<span>12x</span></span><span>
Simplify: (Show steps)</span><span><span>−<span>2x</span></span>=<span>12x</span></span>
Step 2: Subtract 12x from both sides.<span><span><span>−<span>2x</span></span>−<span>12x</span></span>=<span><span>12x</span>−<span>12x</span></span></span><span><span>−<span>14x</span></span>=0</span>
Step 3: Divide both sides by -14.<span><span><span>−<span>14x</span></span><span>−14</span></span>=<span>0<span>−14</span></span></span><span>x=<span>0
You never specified what the (x4) part was so I gave both.</span></span>
Answer:
242cm^2
Step-by-step explanation:
The formula for surface area of a rectangular(assuming that's what you have) is Perimeter of the Base(height) + 2(Area of the Base)
Or you could add up all the sides, or use this formula
SA=2(length*width)+2(length*height)+2(height*width)
2×(10×7 + 10×3 + 7×3)
helpful links:
https://www.khanacademy.org/math/ basic-geo/basic-geo-volume-sa/basic-geometry-surface-area/v/surface-area-of-a-box
http://www.math.com/tables/geometry/surfareas.htm
https://www.basic-mathematics.com/surface-area-formula.html
Answer: SAS is the correct criteria
Explanation:
Angles VMU and GMH are congruent by the Vertical Angles Theorem. Given that angles UVM and GHM are congruent because they are both right angles, we now have two pairs of corresponding angles. Also given that sides HM and VM are congruent, we now have two corresponding pairs of congruent angles and a pair of congruent sides.Therefore, your best option is the ASA postulate, which states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. Therefore, we have a corresponding angle, a corresponding side, and another corresponding angle in triangle GHM, which is congruent to its corresponding angle, a corresponding side, and another corresponding angle in triangle UVM.
Answer:
-42x^4 + 6x^3 + 24x^2
Step-by-step explanation:
