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2 years ago

Whats the difference between "6 + A" and "6 x A"

Mathematics

1 answer:

Nata [24]2 years ago

6 0

Answer:

To determine what is the difference between "6 + A" and "6 x A", the logic of the proposed mathematical operations must be explained:

In "6 + A", the value A is added to the initial value 6. Thus, for example, if A were worth 10, to the initial value 6 10 units are added, with which the final value is 16.

In contrast, in "6 x A", the initial value 6 is multiplied by as many times as the value A indicates. Therefore, continuing with the value of A as 10, in this case 6 would be multiplied by 10 times, giving a final value of 60.

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Answer:

The answer is the second one because it is less than or equal to 35

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2 years ago

60% of a number is 567. what is 50% of the number

lozanna [386]

Answer:

945

Step-by-step explanation:

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2 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

3 years ago

2−2s=4/3 s+13 how do you do this

soldi70 [24.7K]

Answer: s = -3.3

<u>Step-by-step explanation:</u>

$2-2s=\dfrac{4}{3}s+13\\\\\\\underline{\text{Multiply everything by 3 to clear the denominator:}}\\(3)2-(3)2s=(3)\dfrac{4}{3}s+(3)13\\\\.\qquad 6-6s=4s+39\\\\\\\underline{\text{Add 6s to both sides:}}\\.\qquad 6-6s+6s=4s+6s+39\\\\.\qquad \qquad \qquad 6=10s+39\\\\\\\underline{\text{Subtract 39 from both sides:}}\\.\qquad \qquad 6-39=10s+39-39\\\\.\qquad \quad \quad -33=10s\\\\\\\underline{\text{Divide both sides by 10:}}\\.\qquad \quad \quad \dfrac{-33}{10}=\dfrac{10s}{10}$

-3.3 = s

3 0

2 years ago

Please help me on this question (7th grade math) show your work

lakkis [162]

You can take two of the x and y on the table to find the slope:

y2 - y1 / x2 - x1

Lets use (3, 12) and (4, 15)

15 - 12 / 4 - 3

3/1

The slope is 3

Now you can use the point-slope formula to find the equation: y - y1 = m(x - x1)

y - 9 = 3(x - 2)

y - 9 = 3x -6

y = 3x + 3

So you are correct with choice B.

Hope this helped! Mark as Brainliest Please! :)))

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3 years ago