Which graph below shows the solution set for the inequality b ≥ 5? pls help meeeeeeeee

Mathematics

1 answer:

Sliva [168]3 years ago

7 0

Answer: we can’t see graphs but I can help you if you show me them

Step-by-step explanation:

You might be interested in

Find the equation of a line that is parallel to

Novosadov [1.4K]

Answer:

g(x) = 3x - 3

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

If a line is parallel to another, they have the same slope.

Step 1: Define variables

m = 3

Random pt (2, 3)

y = 3x + b

Step 2: Find b

3 = 3(2) + b

3 = 6 + b

b = -3

Step 3: Write parallel linear equation

y = 3x - 3

7 0

3 years ago

Is this the correct answer, yall?

ehidna [41]

Yes, yes it is; well done.

4 0

3 years ago

Find the curl of ~V ~V = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$